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General SciencePhysics: Work, Energy and Power

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A block is pulled with a force of 20 N for a distance of 10 m in the direction of the force. What is the work done?

200 Joules

100 Joules

2 Joules

20 Joules

Correct Answer

🔬 SC • Science Concept & PrincipleGeneral SciencePhysics: Work, Energy and Power

Option A

200 Joules

Quick Summary:

Work done is defined as the product of the force applied and the displacement in the direction of that force. Since the force is applied in the same direction as the displacement, the work done is the simple product of $20 \text{ N}$ and $10 \text{ m}$ .

🔬SCScience SolutionConcept & Principle

💡 Explanation

💡 Everyday Analogy (Real-World Intuition)

Pushing a grocery cart forward across a smooth floor is like applying force in the direction of movement; the more you push or the further you walk, the more work you perform.

🧠 Memory Mnemonic / Shortcut Aid

WFS (Work = Force $\times$ Sliding/Displacement)

🔢 Key Formulas

$W = F \times s$

$W = F \cdot s \cdot \cos(\theta)$

⚙️ Working Principle

According to the mechanical definition of work, $W = F \cdot s \cdot \cos(\theta)$ , where $F$ is force, $s$ is displacement, and $\theta$ is the angle between them. Here, the force and displacement are in the same direction, meaning $\theta = 0°$ . Since $\cos(0°) = 1$ , the expression simplifies to $W = F \times s$ .

📌 Key Points

▸
Work is a scalar quantity, despite being the product of two vector quantities (Force and Displacement).
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The SI unit of work is the Joule ( $\text{J}$ ), where $1 \text{ Joule} = 1 \text{ Newton} \cdot \text{ meter}$ .
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If the force is perpendicular to displacement, the work done is zero.

🛠️ Applications / Uses

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Calculating the energy expended to move heavy objects in a warehouse.
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Designing mechanical systems for lifting weights in construction.

📄 Additional Information

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The calculation is $20 \text{ N} \times 10 \text{ m} = 200 \text{ N}\cdot\text{m} = 200 \text{ J}$ .
▸
Option B (100 Joules) results if one incorrectly divides force by distance. Option D (20 Joules) results if one assumes the displacement is $1 \text{ m}$ .

📊 Diagram / Illustration

✅

A is correct — Work is the scalar product of force and displacement, calculated as $20 \text{ N} \times 10 \text{ m} = 200 \text{ Joules}$ .

Core Concepts Used

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Scalar product Mechanical work Energy transfer

💡 EXAM TIP

Always check the angle $\theta$ between force and displacement in physics problems; if the force is at an angle, you must use $\cos(\theta)$ to find the component of force in the direction of movement.

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