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A body of mass 10 kg is accelerated at 2 m/s². What is the force acting on it?
20 N
5 N
12 N
2 N
20 N
The force acting on a body is calculated using Newton's Second Law of Motion. Given a mass m=10 kg and acceleration a=2 m/s2, the force is the product of mass and acceleration, resulting in 20 N.
The force acting on a body is calculated using Newton's Second Law of Motion. Given a mass m=10 kg and acceleration a=2 m/s2, the force is the product of mass and acceleration, resulting in 20 N.
Pushing an empty shopping cart requires less force than pushing a fully loaded one to achieve the same speed, illustrating that force depends on both mass and how quickly you change its motion.
Remember 'FMA' (Force, Mass, Acceleration) to recall the equation F=m×a.
F=m×a — Newton's Second Law of Motion relating Force (F), Mass (m), and Acceleration (a).
Newton's Second Law states that the force applied to an object is directly proportional to its mass and the acceleration it produces. Mathematically, it is expressed as F=ma, where F is force in Newtons, m is mass in kilograms, and a is acceleration in meters per second squared.
The SI unit of force is the Newton (N), defined as 1 kg⋅m/s2.
Force is a vector quantity, meaning it has both magnitude and direction.
Acceleration is proportional to the net force and inversely proportional to the mass of the object.
Provides a simple, universal method to calculate dynamics in classical mechanics.
Limited to non-relativistic speeds and classical macroscopic systems.
Designing engine power requirements for vehicles.
Calculating structural loads in engineering projects.
Option B (5 N) is incorrect; result of 10/2=5.
Option C (12 N) is incorrect; likely results from calculation errors.
Option D (2 N) is incorrect; result of mass divided by force or incorrect unit interpretation.
A is correct — The force acting on the body is calculated as the product of its mass and acceleration, resulting in 20 N.
Always ensure mass is in kilograms (kg) and acceleration in meters per second squared (m/s²) before calculating to get the force directly in Newtons (N).
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