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A can complete work in 15 days, and B in 20 days. If both work together for 4 days, what fraction of the work remains?
157тАЛ
158тАЛ
1511тАЛ
1513тАЛ
158тАЛ
Calculate LCM of 15 and 20 (60). Efficiency of A is 4 units/day and B is 3 units/day. In 4 days, they complete 4├Ч(4+3)=28 units. Remaining work is 60тИТ28=32 units. Fraction remaining is 6032тАЛ=158тАЛ.
A completes work in 15 days, B in 20 days. Both work together for 4 days.
Work┬аDone=Time├Ч(AтАЩs┬аefficiency+BтАЩs┬аefficiency)
Calculate LCM of 15 and 20 (60). Efficiency of A is 4 units/day and B is 3 units/day. In 4 days, they complete 4├Ч(4+3)=28 units. Remaining work is 60тИТ28=32 units. Fraction remaining is 6032тАЛ=158тАЛ.
Students often calculate the fraction of work completed (6028тАЛ=157тАЛ) and mark Option A, forgetting the question asks for the fraction that remains.
Calculate LCM and Efficiencies
Assume total work as the LCM of 15 and 20, which is 60 units. A's efficiency is 1560тАЛ=4 units/day and B's efficiency is 2060тАЛ=3 units/day.
Total┬аWork=60,AeffтАЛ=4,BeffтАЛ=3
Calculate work done in 4 days
Both work together for 4 days with a combined efficiency of 4+3=7 units/day.
4├Ч(4+3)=28┬аunits
Calculate remaining work fraction
Subtract the work done from total work: 60тИТ28=32. The remaining fraction is the remaining work divided by total work.
6032тАЛ=158тАЛ
B is correct because the remaining work is 32 units out of 60, which simplifies to 8/15.
This unit-based approach is applicable to Pipe and Cistern problems as well, where 'units' represent volume and 'efficiency' represents the rate of water flow.