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A charge of 10 nC is moving with a velocity of 10⁷(−0.5āx+āy−0.71āz) m/s. What will be the force exerted on the charge due to magnetic induction B = (āx+2āy+3āz) mWb/m² and electric field E = (3āx+2āy+āz) kV/m?
(0.47āx+0.1āy−0.91āz) mN
(4.7āx+āy−9.1āz) mN
(0.47āx+0.1āy−0.91āz) N
(4.7āx+āy−9.1āz) kN
(0.47āx+0.1āy−0.91āz) mN
Practice and solve "A charge of 10 nC is moving with a velocity of 107(−0.5āx+āy−0.71āz) m/s. What wil..." for Electrical - Electromagnetics Field Theory . The correct answer is Option A: (0.47āx+0.1āy−0.91āz) mN. Detailed step-by-step solution, conceptual clarity, and formulas on Examoogle.
Option **(a) **