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A man walks 10 km North, turns right and walks 5 km, then turns right again and walks 10 km. How far is he from the starting point?
5 km
10 km
15 km
20 km
5 km
When a person moves a certain distance in one direction, turns and moves perpendicularly, and then moves the exact same distance in the opposite direction, the opposing movements cancel out, and the net displacement equals the intermediate perpendicular segment.
When a person moves a certain distance in one direction, turns and moves perpendicularly, and then moves the exact same distance in the opposite direction, the opposing movements cancel out, and the net displacement equals the intermediate perpendicular segment.
Initial Movement
The man starts from the origin and walks 10 km North.
First Right Turn
He turns right to face East and walks 5 km.
Second Right Turn
He turns right again to face South and walks 10 km. This 10 km South movement completely cancels out the initial 10 km North movement.
Final Distance Calculation
With the vertical movements neutralized, his final position is 5 km East of the starting point, giving a direct distance of 5 km.
B: 10 km is incorrect because the 10 km North and 10 km South movements cancel each other out. C: 15 km is incorrect because it incorrectly adds all path segments together. D: 20 km is incorrect as it results from an erroneous total sum of the entire path length.
A is correct because the 10 km North and 10 km South movements cancel each other out, leaving a net distance of 5 km East from the starting point.
Always look for opposing directions like North-South or East-West that cancel each other out to quickly find net displacement without complex Pythagorean calculations.
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