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A man walks 5 km towards the North, then turns right and walks 3 km, then turns right again and walks 5 km. How far is he from the starting point?
3 km
5 km
8 km
13 km
3 km
When a person moves along a path with equal and opposite vertical segments (North 5 km and South 5 km), the net displacement equals the intermediate perpendicular distance (3 km).
When a person moves along a path with equal and opposite vertical segments (North 5 km and South 5 km), the net displacement equals the intermediate perpendicular distance (3 km).
Initial Movement North
The man starts from the origin (0,0) and walks 5 km North, reaching coordinate (0, 5).
First Right Turn East
Turning right from North leads East. Walking 3 km shifts his position to (3, 5).
Second Right Turn South
Turning right again faces South. Walking 5 km brings him down to (3, 0), making his straight-line distance from the start 3 km.
B: 5 km incorrectly assumes the distance equals one of the vertical legs. C: 8 km is the total distance traveled (5 + 3 + 5), not the straight-line displacement. D: 13 km is an incorrect sum of all values.
A is correct because the 5 km North and 5 km South movements cancel each other vertically, leaving a net horizontal distance of 3 km from the starting point.
Always differentiate between total distance traveled (sum of all segments) and displacement (shortest straight-line distance from start to finish).
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