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ElectricalPower System
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A power system network with a capacity of 100 MVA has a source impedance of 10% at a point ┬╖ The fault level at that point is

A

10 MVA

B

30 MVA

C

3000 MVA

D

1000 MVA

Correct Answer

тЪЩя╕П TE тАв Technical Direct FormulaElectricalPower System
Option D

1000 MVA

Quick Summary:

Given: Base MVA = 100 MVA, Source impedance percentage = 10% (0.10 p.u.)

ЁЯУРMAMath SolutionDirect Formula
ЁЯУЛ Given

Base MVA = 100 MVA, Source impedance percentage = 10% (0.10 p.u.)

ЁЯФв Formula Used

Fault┬аlevel┬а(MVA)=Base┬аMVAPer┬аUnit┬аImpedanceFault\ level\ (MVA) = \frac{Base\ MVA}{Per\ Unit\ Impedance}Fault┬аlevel┬а(MVA)=Per┬аUnit┬аImpedanceBase┬аMVAтАЛ

ЁЯФв Step-by-Step Solution
1

Identify given parameters

The base capacity is given as Sbase=100┬аMVAS_{base} = 100\ MVASbaseтАЛ=100┬аMVA and the percentage impedance ZpuZ_{pu}ZpuтАЛ is 10%=0.110\% = 0.110%=0.1.

Sbase=100┬аMVA,┬аZpu=0.1S_{base} = 100\ MVA, \ Z_{pu} = 0.1SbaseтАЛ=100┬аMVA,┬аZpuтАЛ=0.1

2

Apply fault level formula

The fault level (Short Circuit MVA) is calculated by dividing the base capacity by the per unit impedance.

Sfault=SbaseZpuS_{fault} = \frac{S_{base}}{Z_{pu}}SfaultтАЛ=ZpuтАЛSbaseтАЛтАЛ

3

Calculate the result

Substituting the values into the formula gives Sfault=100/0.1=1000┬аMVAS_{fault} = 100 / 0.1 = 1000\ MVASfaultтАЛ=100/0.1=1000┬аMVA.

Sfault=1000.1=1000┬аMVAS_{fault} = \frac{100}{0.1} = 1000\ MVASfaultтАЛ=0.1100тАЛ=1000┬аMVA

тЬЕ

D is correct because the fault level is calculated as the base capacity divided by the per-unit impedance, resulting in 1000 MVA.

Core Concepts Used
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Per unit system Fault level calculation Short circuit MVA
ЁЯТб EXAM TIP

This concept is fundamental for sizing circuit breakers; in practice, you must also consider the contribution of downstream motors and generator transient reactances.

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