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CivilSoil Mechanics
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A soil sample has porosity of 20 % and its void ratio will be close to

A

2

B

8

C

1

D

25

Correct Answer

тЪЩя╕П TE тАв Technical Direct FormulaCivilSoil Mechanics
Option D

25

Quick Summary:

Given: Porosity (n) = 20% = 0.20

ЁЯУРMAMath SolutionDirect Formula
ЁЯУЛ Given

Porosity (n) = 20% = 0.20

ЁЯФв Formula Used

e=n1тИТne = \frac{n}{1 - n}e=1тИТnnтАЛ

ЁЯФв Step-by-Step Solution
1

Identify given parameters

The porosity nnn is given as 20%, which in decimal form is n=0.20n = 0.20n=0.20.

n=0.20n = 0.20n=0.20

2

State the relationship formula

The relationship between void ratio eee and porosity nnn is given by the formula e=n1тИТne = \frac{n}{1-n}e=1тИТnnтАЛ.

e=n1тИТne = \frac{n}{1 - n}e=1тИТnnтАЛ

3

Substitute and solve

Substituting n=0.20n = 0.20n=0.20 into the formula, we get e=0.201тИТ0.20=0.200.80e = \frac{0.20}{1 - 0.20} = \frac{0.20}{0.80}e=1тИТ0.200.20тАЛ=0.800.20тАЛ.

e=0.200.80=0.25e = \frac{0.20}{0.80} = 0.25e=0.800.20тАЛ=0.25

тЬЕ

D is correct because by substituting the porosity value of 0.2 into the conversion formula, we obtain a void ratio of 0.25.

Core Concepts Used
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Porosity Void Ratio Soil Phase Relationships
ЁЯТб EXAM TIP

Understanding the relationship between porosity and void ratio is foundational for calculating degree of saturation and unit weight of soils in later geotechnical chapters.

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