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A sum of money doubles itself in 5 years at simple interest. In how many years will it become 4 times the original amount?
10 years
12 years
15 years
20 years
15 years
Use the formula T2тАЛ=T1тАЛ├Ч(n1тАЛтИТ1)(n2тАЛтИТ1)тАЛ, where n is the multiplier of the principal.
A sum of money doubles itself in 5 years at simple interest. We need to find the time taken for it to become 4 times the original amount.
SI=100P├ЧR├ЧTтАЛ
Use the formula T2тАЛ=T1тАЛ├Ч(n1тАЛтИТ1)(n2тАЛтИТ1)тАЛ, where n is the multiplier of the principal.
Many students mistake 'becomes 4 times' for 'interest is 4 times'. Always remember that Amount=Principal+Interest, so for 4 times the amount, the interest is 3P.
Analyze the first condition
If the sum doubles, Amount = 2P. Therefore, Simple Interest SI=2PтИТP=P. Given time T1тАЛ=5 years.
P=100P├ЧR├Ч5тАЛтЯ╣R=20%
Analyze the second condition
We want the sum to become 4 times, so Amount = 4P. Therefore, Simple Interest SI=4PтИТP=3P. We need to find T2тАЛ using the rate R=20%.
3P=100P├Ч20├ЧT2тАЛтАЛ
Solve for T2
Solving for T2тАЛ: 3P=5P├ЧT2тАЛтАЛ, which simplifies to T2тАЛ=3├Ч5=15.
T2тАЛ=15┬аyears
C is correct because for the money to become 4 times, the interest earned must be 3 times the principal, which requires 3 times the duration required to earn 1 time the principal as interest.
This ratio method works for any multiple-sum problem in simple interest; remember that the interest portion is always nтИТ1 times the principal.