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A sum of money doubles itself in 8 years at simple interest. In how many years will it become four times itself?
16 years
20 years
24 years
32 years
24 years
Use the formula T2тАЛ=T1тАЛ├Чn1тАЛтИТ1n2тАЛтИТ1тАЛ, where n is the multiplier of the principal. Here, T1тАЛ=8, n1тАЛ=2, and n2тАЛ=4.
A sum of money doubles itself in 8 years under Simple Interest. We need to find the time required for it to become 4 times itself.
T2тАЛ=T1тАЛ├Чn1тАЛтИТ1n2тАЛтИТ1тАЛ
Use the formula T2тАЛ=T1тАЛ├Чn1тАЛтИТ1n2тАЛтИТ1тАЛ, where n is the multiplier of the principal. Here, T1тАЛ=8, n1тАЛ=2, and n2тАЛ=4.
Many students mistakenly assume that if it doubles in 8 years, it will quadruple in 16 years, forgetting that interest is earned only on the initial principal, not on the total accumulated amount.
Calculate the Interest Rate
If the sum P becomes 2P in 8 years, the Simple Interest earned is I=2PтИТP=P. Using the formula I=100P├ЧR├ЧTтАЛ, we get P=100P├ЧR├Ч8тАЛ.
R=8100тАЛ=12.5%
Set target conditions
For the money to become 4 times itself, the total amount A must be 4P. Therefore, the Simple Interest required is I=4PтИТP=3P.
I=3P
Calculate the time
Substitute I=3P and R=12.5 into the formula T=P├ЧR100├ЧIтАЛ.
T=P├Ч12.5100├Ч3PтАЛ=12.5300тАЛ=24
C is correct because the simple interest grows linearly, requiring 8 years to gain 100% of the principal, and thus 24 years to gain 300% (triple the interest).
This concept is identical to solving problems involving arithmetic progression where the common difference is the annual interest earned on the initial principal.