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Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
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CivilAdvanced Survey
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A tacheometer is setup at A and the readings on the staff at B are 1.m, 2.m, 3m and the inclination of line of sight is + 10°. Calculate the vertical distance. Take k = 100, c = 0?

A

34.00 m34.00\text{ m}34.00 m

B

34.202 m34.202\text{ m}34.202 m

C

35.202 m35.202\text{ m}35.202 m

D

36.202 m36.202\text{ m}36.202 m

Correct Answer

⚙️ TE • Technical Direct FormulaCivilAdvanced Survey
Option B

34.202 m34.202\text{ m}34.202 m

Quick Summary:

Given: Staff readings = 1.0 m, 2.0 m, 3.0 m, Angle of inclination θ=+10°\theta = +10°θ=+10°, Multiplying constant k=100k = 100k=100, Additive constant c=0c = 0c=0

📐MAMath SolutionDirect Formula
📋 Given

Staff readings = 1.0 m, 2.0 m, 3.0 m, Angle of inclination θ=+10°\theta = +10°θ=+10°, Multiplying constant k=100k = 100k=100, Additive constant c=0c = 0c=0

🔢 Formula Used

V=k⋅S⋅sin⁡(2θ)2+c⋅sin⁡(θ)V = k \cdot S \cdot \frac{\sin(2\theta)}{2} + c \cdot \sin(\theta)V=k⋅S⋅2sin(2θ)​+c⋅sin(θ)

📊 Diagram / Illustration
θ=10∘\theta = 10^\circθ=10∘
Station AStation B
VVV
3.0 m2.0 m1.0 m
🔢 Step-by-Step Solution
1

Calculate Staff Intercept (SSS)

The staff intercept SSS is the difference between the top hair reading (StopS_{top}Stop​) and the bottom hair reading (SbottomS_{bottom}Sbottom​).

S=Stop−Sbottom=3.0 m−1.0 m=2.0 mS = S_{top} - S_{bottom} = 3.0\text{ m} - 1.0\text{ m} = 2.0\text{ m}S=Stop​−Sbottom​=3.0 m−1.0 m=2.0 m

2

Apply Vertical Distance Formula

For an inclined line of sight, the formula for vertical distance VVV is V=k⋅S⋅sin⁡(θ)⋅cos⁡(θ)+c⋅sin⁡(θ)V = k \cdot S \cdot \sin(\theta) \cdot \cos(\theta) + c \cdot \sin(\theta)V=k⋅S⋅sin(θ)⋅cos(θ)+c⋅sin(θ), which simplifies using trigonometric identity sin⁡(2θ)=2sin⁡(θ)cos⁡(θ)\sin(2\theta) = 2 \sin(\theta) \cos(\theta)sin(2θ)=2sin(θ)cos(θ).

V=k⋅S⋅sin⁡(2θ)2+c⋅sin⁡(θ)V = k \cdot S \cdot \frac{\sin(2\theta)}{2} + c \cdot \sin(\theta)V=k⋅S⋅2sin(2θ)​+c⋅sin(θ)

3

Substitute Values and Solve

Substitute k=100k = 100k=100, S=2.0 mS = 2.0\text{ m}S=2.0 m, θ=10°\theta = 10°θ=10°, and c=0c = 0c=0 into the formula.

V=100×2.0×sin⁡(20°)2=100×sin⁡(20°)V = 100 \times 2.0 \times \frac{\sin(20°)}{2} = 100 \times \sin(20°)V=100×2.0×2sin(20°)​=100×sin(20°)

4

Final Numerical Calculation

Since sin⁡(20°)≈0.3420201\sin(20°) \approx 0.3420201sin(20°)≈0.3420201, we multiply by 100100100 to get the vertical distance.

V=100×0.3420201=34.202 mV = 100 \times 0.3420201 = 34.202\text{ m}V=100×0.3420201=34.202 m

✅

B is correct because calculating V=100×2.0×sin⁡(10°)cos⁡(10°)V = 100 \times 2.0 \times \sin(10°) \cos(10°)V=100×2.0×sin(10°)cos(10°) gives exactly 34.202 m34.202\text{ m}34.202 m.

Core Concepts Used
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Staff Intercept Tacheometric Constants Inclined Line of Sight
💡 EXAM TIP

In tacheometry questions, if the staff is held vertical (standard case), use V=kSsin⁡(θ)cos⁡(θ)+csin⁡(θ)V = k S \sin(\theta) \cos(\theta) + c \sin(\theta)V=kSsin(θ)cos(θ)+csin(θ). If the staff is normal to the line of sight, the formula changes to V=(kS+c)sin⁡(θ)V = (k S + c) \sin(\theta)V=(kS+c)sin(θ).

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