Identify given parameters

From the question, we have staff intercept $s = 1.5\text{ m}$, multiplying constant $k = 100$, and additive constant $c = 0$. The line of sight is horizontal.

$s = 1.5\text{ m}, \quad k = 100, \quad c = 0$

Apply horizontal distance formula

For a horizontal line of sight in tacheometry, the horizontal distance $D$ between station $A$ and staff $B$ is given by $D = k \cdot s + c$.

$D = 100 \times 1.5 + 0 = 150\text{ m}$

Determine vertical distance

Since the line of sight is horizontal, the vertical angle $\theta = 0°$. Therefore, vertical distance $V = D \tan(0°) = 0\text{ m}$. Hence, the elevation difference/vertical component between the line of sight and target is $0\text{ m}$. However, in standard exam nomenclature for horizontal line of sight questions where option B is $150\text{ m}$ (horizontal distance) and option C is $0\text{ m}$ (vertical distance), the answer for vertical distance is $0\text{ m}$.

$V = 0\text{ m}$