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An electric refrigerator rated 400 W operates 8 hours/day. What is the cost of the energy to operate it for 30 days at ₹3.00 per kW h?
₹400
₹36
₹288
₹9.6
₹288
The correct answer is Option C (₹288). The total electrical energy consumed by an appliance depends on its power rating, the duration of operation per day, and the total number of days.
The correct answer is Option C (₹288). The total electrical energy consumed by an appliance depends on its power rating, the duration of operation per day, and the total number of days.
If a light bulb consumes 1 unit of electricity every day, in 30 days it will consume 30 units, and the total bill will simply be 30 times the cost per unit.
E=P×t — Electrical energy consumed
1 kWh=1 Unit=3.6×106 J — Commercial unit of energy
Electrical energy (E) consumed by an appliance is given by the product of its power rating (P) and the total time (t) for which it is used. Since commercial electrical energy is measured in kilowatt-hours (1 kWh=1 unit), power in watts is converted to kilowatts by dividing by 1000.
Power rating of the refrigerator, P=400 W=1000400 kW=0.4 kW.
Total operating time for 30 days, t=8 hours/day×30 days=240 hours.
Total energy consumed, E=0.4 kW×240 h=96 kWh.
Total cost =96 kWh×₹3.00/kWh=₹288.
Calculation of monthly electricity bills for household appliances.
Designing energy-efficient electrical systems.
Option A (₹400) is incorrect as it uses the power value directly without proper unit conversion.
Option B (₹36) is incorrect as it calculates energy for a single day instead of 30 days (0.4×8×3=₹9.6 is incorrect calculation error).
Option D (₹9.6) is incorrect because it represents the cost of energy consumed in just 1 day (0.4 kW×8 h×₹3.00=₹9.6).
C is correct — The total energy consumed in 30 days is 96 kWh, costing 96×3=₹288.
Always remember to convert power to kilowatts (kW) and time to hours (h) before calculating commercial energy units (kWh).