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ElectricalPower System
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An isolated synchronous generator with transient reactance of 0.1 pu on a 100 MVA base is connected to the high voltage bus through a step up transformer of reactance 0.1 pu on a 100 MVA base. Fault level at the bus is

A

1000 MVA

B

500 MVA

C

50 MVA

D

10 MVA

Correct Answer

тЪЩя╕П TE тАв Technical Concept & PrincipleElectricalPower System
Option B

500 MVA

Quick Summary:

The fault level at a bus is defined as the product of the base MVA and the reciprocal of the total per-unit reactance (subtransient) looking into the fault point. In this case, the generator and transformer are in series, so their reactances add up, resulting in a total equivalent reactance of 0.2┬аpu0.2 \text{ pu}0.2┬аpu.

тЪЩя╕ПTETechnical SolutionConcept & Principle
ЁЯТб Explanation

The fault level at a bus is defined as the product of the base MVA and the reciprocal of the total per-unit reactance (subtransient) looking into the fault point. In this case, the generator and transformer are in series, so their reactances add up, resulting in a total equivalent reactance of 0.2┬аpu0.2 \text{ pu}0.2┬аpu.

ЁЯФв Key Formulas

Sfault=SbaseXtotal(pu)S_{fault} = \frac{S_{base}}{X_{total(pu)}}SfaultтАЛ=Xtotal(pu)тАЛSbaseтАЛтАЛ тАФ Formula to calculate fault MVA

Xtotal=Xgen+XtransX_{total} = X_{gen} + X_{trans}XtotalтАЛ=XgenтАЛ+XtransтАЛ тАФ Series addition of reactances

тЪЩя╕П Working Principle

The short-circuit capacity (Fault Level) is calculated as Sfault=SbaseXeq(pu)S_{fault} = \frac{S_{base}}{X_{eq(pu)}}SfaultтАЛ=Xeq(pu)тАЛSbaseтАЛтАЛ. Since the generator is connected to the bus through a transformer, the total reactance seen from the bus during a fault is Xgen+Xtrans=0.1+0.1=0.2┬аpuX_{gen} + X_{trans} = 0.1 + 0.1 = 0.2 \text{ pu}XgenтАЛ+XtransтАЛ=0.1+0.1=0.2┬аpu. Dividing the 100 MVA base by 0.2 gives 500 MVA.

ЁЯУМ Key Points
  • тЦ╕

    Fault level is inversely proportional to the per-unit impedance.

  • тЦ╕

    Per-unit values remain consistent only when calculated on the same MVA base.

  • тЦ╕

    The transient reactance is used to calculate the subtransient fault level for standard breaker rating studies.

тЬЕ Advantages
  • тЦ╕

    Simplifies complex multi-machine system analysis.

  • тЦ╕

    Allows direct comparison of fault severity across different voltage levels.

тЭМ Disadvantages / Limitations
  • тЦ╕

    Does not account for resistance (RRR), which is often ignored for simplicity.

  • тЦ╕

    Transient behavior varies over time (subtransient vs transient vs steady state).

ЁЯЫая╕П Applications / Uses
  • тЦ╕

    Rating of circuit breakers and switchgear.

  • тЦ╕

    Design of protective relaying systems.

  • тЦ╕

    Determining the capacity of busbars and bus-ducts.

ЁЯУД Additional Information
  • тЦ╕

    Standard procedure: Always check if the base MVA is consistent for all components.

  • тЦ╕

    If reactance was given on different bases, we would first convert them to a common MVA base.

ЁЯУК Diagram / Illustration
Fault Level Calculation
Sfault=SbaseXeq(pu)S_{fault} = \frac{S_{base}}{X_{eq(pu)}}SfaultтАЛ=Xeq(pu)тАЛSbaseтАЛтАЛ
100┬аMVA100 \text{ MVA}100┬аMVA
0.1+0.1=0.2┬аpu0.1 + 0.1 = 0.2 \text{ pu}0.1+0.1=0.2┬аpu
Sfault=500┬аMVAS_{fault} = 500 \text{ MVA}SfaultтАЛ=500┬аMVA
тЬЕ

B is correct тАФ The total reactance is 0.2┬аpu0.2 \text{ pu}0.2┬аpu, and dividing 100┬аMVA100 \text{ MVA}100┬аMVA by 0.2┬аpu0.2 \text{ pu}0.2┬аpu yields 500┬аMVA500 \text{ MVA}500┬аMVA.

Core Concepts Used
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Fault Level Analysis Per-Unit System Synchronous Machine Reactance
ЁЯТб EXAM TIP

Always ensure the MVA base is the same for all components before adding per-unit impedances; otherwise, perform a base conversion.

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