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An object of mass 5 kg is thrown vertically upwards with an initial velocity of 20 m/s. What is the maximum height reached by the object? (Take g = 10 m/s┬▓)
20 m
10 m
15 m
25 m
20 m
At the maximum height, the final velocity of the object becomes 0 m/s. By applying the third equation of motion, we can calculate the distance traveled against gravity before the object comes to a momentary stop.
At the maximum height, the final velocity of the object becomes 0 m/s. By applying the third equation of motion, we can calculate the distance traveled against gravity before the object comes to a momentary stop.
Think of throwing a ball straight up like an athlete jumping; you lose speed as you go higher until you hit your peak height and start falling back down.
UVAS: Use v2тИТu2=2as when time is not mentioned.
v2=u2+2as тАФ The third equation of motion used to relate displacement, velocity, and acceleration.
h=2gu2тАЛ тАФ Derived formula for maximum height reached by an object thrown upwards.
The principle of conservation of energy or the laws of motion under constant acceleration apply here. As the object rises, its initial kinetic energy is converted into gravitational potential energy. Since the acceleration due to gravity g acts in the opposite direction of motion, it causes a uniform retardation until the velocity becomes zero.
At maximum height, the final velocity v is always 0.
Gravity g is taken as тИТ10m/s2 because it opposes upward motion.
The mass of the object does not affect the maximum height reached in the absence of air resistance.
Projectile motion analysis in sports.
Calculating trajectory of launched objects.
Calculation: 02=202+2(тИТ10)h implies 0=400тИТ20h, therefore 20h=400 and h=20m.
Option B (10m) is incorrect as it results from miscalculating v2=u2+2as or forgetting the 2 in the denominator.
A is correct тАФ The maximum height reached by the object is 20 meters.
When solving motion problems, always check if the question mentions 'time'. If time is missing, jump straight to the third equation of motion: v2тИТu2=2as.
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