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CivilStructural Mechanics-II
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At the centre of simply supported beam, deflection is _________ and slope is _________.

A

Maximum, Maximum

B

Zero, Maximum

C

Maximum, Zero

D

Zero, Zero

Correct Answer

тЪЩя╕П TE тАв Technical Concept & PrincipleCivilStructural Mechanics-II
Option C

Maximum, Zero

Quick Summary:

In a simply supported beam subjected to symmetric loading (like a point load at the center or uniform distributed load), the deflected shape is symmetric about the mid-span. Due to this symmetry, the tangent to the elastic curve at the center is horizontal, resulting in zero slope, while the vertical displacement reaches its maximum value.

тЪЩя╕ПTETechnical SolutionConcept & Principle
ЁЯТб Explanation

In a simply supported beam subjected to symmetric loading (like a point load at the center or uniform distributed load), the deflected shape is symmetric about the mid-span. Due to this symmetry, the tangent to the elastic curve at the center is horizontal, resulting in zero slope, while the vertical displacement reaches its maximum value.

ЁЯФв Key Formulas

╬┤max=WL348EI\delta_{max} = \frac{WL┬│}{48EI}╬┤maxтАЛ=48EIWL3тАЛ тАФ Maximum deflection for a central point load

╬╕=dydx\theta = \frac{dy}{dx}╬╕=dxdyтАЛ тАФ Definition of slope as the first derivative of deflection

тЪЩя╕П Working Principle

The beam undergoes bending such that the curvature is concave downward (or upward depending on loading). At the center, the internal bending moment is at its peak; since slope (theta=fracdydx\\theta = \\frac{dy}{dx}theta=fracdydx) represents the rate of change of deflection, and the deflection curve reaches a stationary point (peak) at the center, the derivative is zero. Thus, theta=0\\theta = 0theta=0 and delta=deltamax\\delta = \\delta_{max}delta=deltamaxтАЛ.

ЁЯУМ Key Points
  • тЦ╕

    Symmetry in loading and support conditions leads to zero slope at the center of a simply supported beam.

  • тЦ╕

    The maximum deflection occurs where the shear force changes sign (which is at the center for a central point load).

  • тЦ╕

    Slope is maximum at the supports of a simply supported beam.

тЬЕ Advantages
  • тЦ╕

    Predictable structural behavior under symmetric loading.

  • тЦ╕

    Allows for simplified calculation of deflection and slope using double integration or area-moment methods.

тЭМ Disadvantages / Limitations
  • тЦ╕

    Does not hold true for asymmetric loading where the point of zero slope shifts.

  • тЦ╕

    Assumes linear elastic material behavior (Hooke's Law).

ЁЯЫая╕П Applications / Uses
  • тЦ╕

    Structural design of beams in buildings and bridges.

  • тЦ╕

    Mechanical design of shafts and machine components.

ЁЯУД Additional Information
  • тЦ╕

    For a central point load WWW, slope ╬╕=0\theta = 0╬╕=0 at x=L/2x = L/2x=L/2.

  • тЦ╕

    Option B is incorrect because slope is maximum at the supports, not the center.

ЁЯУК Diagram / Illustration
Beam Mid-Span PropertiesDeflection (╬┤) = MaximumSlope (╬╕) = 0
тЬЕ

C is correct тАФ At the center of a symmetric simply supported beam, the deflected shape is horizontal, meaning the slope is zero and the deflection is at its peak.

Core Concepts Used
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Elastic Curve Structural Symmetry Bending Theory
ЁЯТб EXAM TIP

Always verify loading symmetry before assuming zero slope at the center; if the load is eccentric, the point of zero slope (maximum deflection) will shift away from the mid-span.

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