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Based on the English alphabetical order, three of the following four letter cluster pairs are alike in a certain way and thus form a group. Which is the one that does not belong to that group? (Note: The odd man out is not based on the number of consonants/vowels or their position in the letter cluster.)
KI−EF
SQ−NL
AY−VT
LJ−GE
KI−EF
Calculate the difference between the alphabetical positions of letters in each pair (Left-Right) and compare the gaps between pairs.
Calculate the difference between the alphabetical positions of letters in each pair (Left-Right) and compare the gaps between pairs.
Analyze KI-EF
K(11)-I(9) = 2. E(5)-F(6) = -1. The difference between cluster 1 (11-9=2) and cluster 2 (5-6=-1) is 2 - (-1) = 3.
Analyze SQ-NL
S(19)-Q(17) = 2. N(14)-L(12) = 2. The difference between cluster 1 (19-17=2) and cluster 2 (14-12=2) is 2 - 2 = 0.
Analyze AY-VT
A(1)-Y(25) = -24 (or 2). V(22)-T(20) = 2. The difference between cluster 1 (2) and cluster 2 (2) is 2 - 2 = 0.
Analyze LJ-GE
L(12)-J(10) = 2. G(7)-E(5) = 2. The difference between cluster 1 (2) and cluster 2 (2) is 2 - 2 = 0.
B, C, and D are wrong because they follow the pattern where both pairs have a positional difference of 2 (Diff: 2-2=0), while A has a differing pattern.
A is correct because in options B, C, and D, both clusters in the pair have a constant difference of 2, whereas in option A, the second cluster (EF) has a difference of -1.
When checking letter clusters, always convert to numerical values (A=1, B=2...) first; this turns visual puzzles into simple arithmetic problems.
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