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Based on the English alphabetical order, three of the following four letter-cluster pairs are alike in a certain way and thus form a group. Which pair DOES NOT belong to that group? (Note: The odd one out is not based on the number of consonants/vowels or their position in the letter-cluster pair.)
OH-MT
SL-RX
RK-QW
LE-KQ
OH-MT
Convert all letters to their positional values (A=1, Z=26) and find the difference between the first letter and the second, and the third and the fourth.
Convert all letters to their positional values (A=1, Z=26) and find the difference between the first letter and the second, and the third and the fourth.
Analyze positional differences for each pair
A: OH (O=15, H=8, difference 7) and MT (M=13, T=20, difference -7). B: SL (S=19, L=12, difference 7) and RX (R=18, X=24, difference -6). C: RK (R=18, K=11, difference 7) and QW (Q=17, W=23, difference -6). D: LE (L=12, E=5, difference 7) and KQ (K=11, Q=17, difference -6).
Evaluate the pattern
For options B, C, and D, the first letter of the pair minus the second letter is 7, and the third letter minus the fourth letter is -6. Option A shows a difference of 7 for the first pair (15-8=7) but a difference of -7 for the second pair (13-20=-7), making it the odd one out.
B: Follows the +7, -6 pattern; C: Follows the +7, -6 pattern; D: Follows the +7, -6 pattern.
A is correct because it follows a +7, -7 pattern, whereas all other options follow a consistent +7, -6 pattern between the letters of the clusters.
When dealing with letter-cluster odd-one-out questions, always map letters to numbers immediately to reveal underlying arithmetic patterns that are invisible to the naked eye.
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