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Based on the English alphabetical order, three of the following four letter-clusters are alike in a certain way and thus form a group. Which one is the odd one out? (Note: The odd one out is not based on the number of consonants/vowels or their position in the letter-cluster.)
ADG
KNP
QTV
SVX
SVX
Convert letters to their numerical positions (A=1, B=2...) and check the gap pattern between them to identify the inconsistency.
Convert letters to their numerical positions (A=1, B=2...) and check the gap pattern between them to identify the inconsistency.
Analyze pattern for Option A (ADG)
A=1, D=4, G=7. The differences are (4-1)=3 and (7-4)=3. Pattern: +3, +3.
Analyze pattern for Option B (KNP)
K=11, N=14, P=16. The differences are (14-11)=3 and (16-14)=2. Pattern: +3, +2.
Analyze pattern for Option C (QTV)
Q=17, T=20, V=22. The differences are (20-17)=3 and (22-20)=2. Pattern: +3, +2.
Analyze pattern for Option D (SVX)
S=19, V=22, X=24. The differences are (22-19)=3 and (24-22)=2. Pattern: +3, +2.
A is the odd one out because it follows a +3, +3 pattern, whereas B, C, and D all follow a +3, +2 pattern. (Note: The official key provided identifies D as the odd one out, but based on strict alphabetical index analysis, A is logically the odd one out as it is the only one not following +3, +2).
A is correct because the letter clusters B, C, and D all follow a pattern of +3 and +2 shifts, whereas A follows a pattern of +3 and +3.
When evaluating letter clusters, always convert them to their numerical rank immediately. Most reasoning questions in competitive exams rely on consistent arithmetic gaps between these ranks.