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Examoogle • User • info@examoogle.com • EE-2024-8821
Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
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Based on the English alphabetical order, three of the following four letter-cluster pairs are alike in a certain way and thus form a group. Which letter-cluster pair DOES NOT belong to that group? (Note: The odd one out is not based on the number of consonants/vowels or their position in the letter-cluster.)
KG - HD
PL - MI
HD - EA
JF - HT
JF - HT
Quick Trick: Calculate positional differences for both letter pairs in each cluster: First to Second is -4 in all except D where J to F is -4 but H to T is +12.
Calculate positional differences for both letter pairs in each cluster: First to Second is -4 in all except D where J to F is -4 but H to T is +12.
Analyze positional differences in Option A, B, and C
Convert letters to alphabetical position numbers (A=1, B=2, ..., Z=26). For A) KG - HD: K(11) - 4 = G(7) and H(8) - 4 = D(4). For B) PL - MI: P(16) - 4 = L(12) and M(13) - 4 = I(9). For C) HD - EA: H(8) - 4 = D(4) and E(5) - 4 = A(1).
Identify pattern rule
In each pair of clusters, the second letter is obtained by subtracting 4 from the position of the first letter (Difference = -4 for both letter-clusters in the pair).
Check Option D
For D) JF - HT: J(10) - 4 = F(6) follows the rule, but for HT, H(8) to T(20) gives a difference of +12 instead of -4.
A: Follows pattern [K(11)-4=G(7) and H(8)-4=D(4)], B: Follows pattern [P(16)-4=L(12) and M(13)-4=I(9)], C: Follows pattern [H(8)-4=D(4) and E(5)-4=A(1)]
D is correct because in option D, the second letter-cluster HT has a position difference of +12 instead of -4, breaking the pattern followed by options A, B, and C.
Memorize positional values of English letters (EJOTY rule: E=5, J=10, O=15, T=20, Y=25) to solve analogy and odd-one-out questions quickly.