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Examoogle • User • info@examoogle.com • EE-2024-8821
Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
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IKMO
IJKN
HIKN
IJNO
IKMO
Identify the positional shifts: B-1=A, C+0=C, D+1=E, F+2=H. Apply this (+/- sequence: -1, 0, +1, +2) to the target letters.
Identify the positional shifts: B-1=A, C+0=C, D+1=E, F+2=H. Apply this (+/- sequence: -1, 0, +1, +2) to the target letters.
Analyze the pattern of the first pair
B(2) to A(1) is -1; C(3) to C(3) is +0; D(4) to E(5) is +1; F(6) to H(8) is +2. The logic is -1, 0, +1, +2.
Apply the pattern to JKLM
J(10)-1=I(9); K(11)+0=K(11); L(12)+1=M(13); M(13)+2=O(15). This results in IKMO.
B: IJKN is incorrect as N is the 14th letter and the logic requires O. C: HIKN is incorrect because H is the 8th letter, not I (9th). D: IJNO is incorrect as J and N do not follow the derived positional shift pattern.
A is correct because applying the -1, 0, +1, +2 sequence to JKLM yields I, K, M, O respectively.
When solving letter analogies, always write down the numerical positions (A=1, B=2, ...) to quickly identify the arithmetic difference between terms.
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