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Calculate the arithmetic mean of the following data: Class interval 10-20, 20-30, 30-40, 40-50; Frequencies 5, 10, 15, 10.
31.25
32.50
30.00
33.75
32.50
Use the assumed mean method or deviation method (diтАЛ=xiтАЛтИТA) to simplify large numbers and calculate the mean quickly in the exam hall.
Class intervals: 10-20, 20-30, 30-40, 40-50 with frequencies 5, 10, 15, 10 respectively.
x=тИСfiтАЛтИС(fiтАЛтЛЕxiтАЛ)тАЛ
Use the assumed mean method or deviation method (diтАЛ=xiтАЛтИТA) to simplify large numbers and calculate the mean quickly in the exam hall.
Using the lower or upper limit of the class interval directly as xiтАЛ instead of calculating the correct midpoint (xiтАЛ=2Lower┬аlimit+Upper┬аlimitтАЛ).
Find Midpoints (xiтАЛ) for Each Class
Calculate the midpoint for each class interval using the formula xiтАЛ=2Lower┬аlimit+Upper┬аlimitтАЛ. For 10тБ╗┬▓тБ░ it is 15, for 20-30 it is 25, for 30-40 it is 35, and for 40-50 it is 45.
xiтАЛ={15,25,35,45}
Calculate Product of Frequency and Midpoint (fiтАЛтЛЕxiтАЛ)
Multiply each frequency fiтАЛ by its corresponding midpoint xiтАЛ: 5├Ч15=75, 10├Ч25=250, 15├Ч35=525, and 10├Ч45=450.
тИСfiтАЛтЛЕxiтАЛ=75+250+525+450=1300
Find Total Frequency (тИСf_i)
Sum up all the given frequencies to find the total number of observations.
тИСfiтАЛ=5+10+15+10=40
Compute Arithmetic Mean
Apply the arithmetic mean formula for grouped data by dividing the sum of fiтАЛxiтАЛ by the total frequency тИСfiтАЛ.
x=401300тАЛ=32.50
B is correct because the calculated arithmetic mean of the given data is 32.50.
Understanding grouped data central tendencies is essential for solving problems on median, mode, and standard deviation in statistics questions for technical exams.