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ElectricalMachine
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Calculate the magnetic flux density (T) if the magnetic field strength is 2A/m.

A

A) 4╧А├Ч10┬░тИТ74\pi \times 10┬░{-7}4╧А├Ч10┬░тИТ7

B

B) 8╧А├Ч10┬░тИТ78\pi \times 10┬░{-7}8╧А├Ч10┬░тИТ7

C

C) 12╧А├Ч10┬░тИТ712\pi \times 10┬░{-7}12╧А├Ч10┬░тИТ7

D

D) 12.5╧А├Ч10┬░тИТ712.5\pi \times 10┬░{-7}12.5╧А├Ч10┬░тИТ7

Correct Answer

тЪЩя╕П TE тАв Technical Concept & PrincipleElectricalMachine
Option B

8╧А├Ч10┬░тИТ78\pi \times 10┬░{-7}8╧А├Ч10┬░тИТ7

Quick Summary:

The magnetic flux density (BBB) in free space is given by the relation B=╬╝0HB = \mu_0 HB=╬╝0тАЛH, where ╬╝0\mu_0╬╝0тАЛ is the permeability of free space (4╧А├Ч10┬░тИТ7┬аH/m4\pi \times 10┬░{-7} \text{ H/m}4╧А├Ч10┬░тИТ7┬аH/m) and HHH is the magnetic field strength. Substituting H=2┬аA/mH = 2 \text{ A/m}H=2┬аA/m, we get B=(4╧А├Ч10┬░тИТ7)├Ч2=8╧А├Ч10┬░тИТ7┬аTB = (4\pi \times 10┬░{-7}) \times 2 = 8\pi \times 10┬░{-7} \text{ T}B=(4╧А├Ч10┬░тИТ7)├Ч2=8╧А├Ч10┬░тИТ7┬аT. Thus, Option B is the correct answer.

тЪЩя╕ПTETechnical SolutionConcept & Principle
ЁЯТб Explanation

The magnetic flux density (BBB) in free space is given by the relation B=╬╝0HB = \mu_0 HB=╬╝0тАЛH, where ╬╝0\mu_0╬╝0тАЛ is the permeability of free space (4╧А├Ч10┬░тИТ7┬аH/m4\pi \times 10┬░{-7} \text{ H/m}4╧А├Ч10┬░тИТ7┬аH/m) and HHH is the magnetic field strength. Substituting H=2┬аA/mH = 2 \text{ A/m}H=2┬аA/m, we get B=(4╧А├Ч10┬░тИТ7)├Ч2=8╧А├Ч10┬░тИТ7┬аTB = (4\pi \times 10┬░{-7}) \times 2 = 8\pi \times 10┬░{-7} \text{ T}B=(4╧А├Ч10┬░тИТ7)├Ч2=8╧А├Ч10┬░тИТ7┬аT. Thus, Option B is the correct answer.

ЁЯФв Key Formulas

B=╬╝0HB = \mu_0 HB=╬╝0тАЛH тАФ Relation between magnetic flux density (BBB) and magnetic field strength (HHH) in free space

╬╝0=4╧А├Ч10┬░тИТ7┬аH/m\mu_0 = 4\pi \times 10┬░{-7} \text{ H/m}╬╝0тАЛ=4╧А├Ч10┬░тИТ7┬аH/m тАФ Permeability of free space

тЪЩя╕П Working Principle

In free space or air, magnetic flux density (BBB) is directly proportional to magnetic field strength (HHH). The constant of proportionality is the magnetic permeability of free space, denoted as ╬╝0=4╧А├Ч10┬░тИТ7┬аH/m\mu_0 = 4\pi \times 10┬░{-7} \text{ H/m}╬╝0тАЛ=4╧А├Ч10┬░тИТ7┬аH/m. Therefore, multiplying the magnetic field strength by ╬╝0\mu_0╬╝0тАЛ gives the total flux density produced in that region.

ЁЯУМ Key Points
  • тЦ╕

    Magnetic field strength (HHH) is measured in Amperes per meter (A/m) or Ampere-turns per meter (AT/m).

  • тЦ╕

    Magnetic flux density (BBB) is measured in Tesla (T) or Wb/m┬▓.

  • тЦ╕

    In a magnetic medium other than free space, B=╬╝H=╬╝0╬╝rHB = \mu H = \mu_0 \mu_r HB=╬╝H=╬╝0тАЛ╬╝rтАЛH where ╬╝r\mu_r╬╝rтАЛ is the relative permeability of the medium.

ЁЯЫая╕П Applications / Uses
  • тЦ╕

    Calculation of magnetic field intensity and flux density in electrical machine core designs.

  • тЦ╕

    Determining force on current-carrying conductors in magnetic fields.

ЁЯУД Additional Information
  • тЦ╕

    Option A (4╧А├Ч10┬░тИТ7┬аT4\pi \times 10┬░{-7} \text{ T}4╧А├Ч10┬░тИТ7┬аT) corresponds to H=1┬аA/mH = 1 \text{ A/m}H=1┬аA/m.

  • тЦ╕

    Option B (8╧А├Ч10┬░тИТ7┬аT8\pi \times 10┬░{-7} \text{ T}8╧А├Ч10┬░тИТ7┬аT) is correct for H=2┬аA/mH = 2 \text{ A/m}H=2┬аA/m.

  • тЦ╕

    Option C (12╧А├Ч10┬░тИТ7┬аT12\pi \times 10┬░{-7} \text{ T}12╧А├Ч10┬░тИТ7┬аT) corresponds to H=3┬аA/mH = 3 \text{ A/m}H=3┬аA/m.

ЁЯУК Diagram / Illustration
Magnetic Flux Density FormulaB = ┬╡тВА ├Ч HB = (4╧А ├Ч 10тБ╗тБ╖) ├Ч 2 A/mB = 8╧А ├Ч 10тБ╗тБ╖ T
тЬЕ

B is correct тАФ Using B=╬╝0HB = \mu_0 HB=╬╝0тАЛH with ╬╝0=4╧А├Ч10┬░тИТ7┬аH/m\mu_0 = 4\pi \times 10┬░{-7} \text{ H/m}╬╝0тАЛ=4╧А├Ч10┬░тИТ7┬аH/m and H=2┬аA/mH = 2 \text{ A/m}H=2┬аA/m yields B=8╧А├Ч10┬░тИТ7┬аTB = 8\pi \times 10┬░{-7} \text{ T}B=8╧А├Ч10┬░тИТ7┬аT.

Core Concepts Used
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Magnetic Flux Density (B) Magnetic Field Intensity (H) Permeability of Free Space
ЁЯТб EXAM TIP

Remember that BBB and HHH are related by permeability, similar to how electric flux density (DDD) and electric field intensity (EEE) are related by permittivity (D=╧╡ED = \epsilon ED=╧╡E).

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