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Complete the analogy.
DHLP
DGJM
DGLN
EIKN
DHLP
Observe the constant jump: every letter in the second group is exactly +1 position ahead of the corresponding letter in the first group.
Observe the constant jump: every letter in the second group is exactly +1 position ahead of the corresponding letter in the first group.
Analyze the pattern between AEIM and BFJN
Compare each letter positionally: A to B (+1), E to F (+1), I to J (+1), M to N (+1). The transformation rule is constant +1 for each letter.
Apply the rule to CGKO
C+1 = D, G+1 = H, K+1 = L, O+1 = P. Applying the +1 rule to each character in CGKO results in DHLP.
B (DGJM) fails because G, J, M do not follow the +1 shift. C (DGLN) fails because L, N do not follow the +1 shift. D (EIKN) fails because the starting letter should be D, not E.
A is correct because every letter in the sequence CGKO is shifted forward by one position in the English alphabet (C+1=D, G+1=H, K+1=L, O+1=P) to arrive at DHLP.
In alphabetical analogies, always check if the shift is constant across all letters before looking for complex vowel/consonant rules.
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