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Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
Back to Practice Questions
ElectricalElectric Drives
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Counter EMF of the DC motor is

A

Less than the applied voltage

B

More than the applied voltage

C

Equal to the applied voltage

D

None of the above

Correct Answer

Concept & PrincipleElectricalElectric Drives
Option A

Less than the applied voltage

Quick Summary: The counter EMF (or back EMF), denoted as $E_b$, is the induced voltage generated by a DC motor acting as a generator while it rotates in a magnetic field. According to Lenz's law, this voltage always opposes the applied terminal voltage $V$, and due to the inherent voltage drop across the internal armature resistance ($I_a R_a$), it must always be less than the applied voltage to allow current to flow.

💡 Explanation

The counter EMF (or back EMF), denoted as EbE_bEb​, is the induced voltage generated by a DC motor acting as a generator while it rotates in a magnetic field. According to Lenz's law, this voltage always opposes the applied terminal voltage VVV, and due to the inherent voltage drop across the internal armature resistance (IaRaI_a R_aIa​Ra​), it must always be less than the applied voltage to allow current to flow.

🔢 Key Formulas

Eb=V−IaRaE_b = V - I_a R_aEb​=V−Ia​Ra​ — The fundamental voltage balance equation for a DC motor armature.

Eb=PΦZN60AE_b = \frac{P \Phi Z N}{60 A}Eb​=60APΦZN​ — The EMF equation representing the back EMF generation principle.

⚙️ Working Principle

When a DC motor is connected to a supply voltage VVV, current IaI_aIa​ flows into the armature. As the armature conductors cut the magnetic field, an EMF is induced (Eb=PΦZN60AE_b = \frac{P \Phi Z N}{60 A}Eb​=60APΦZN​). The relationship between the supply voltage and back EMF is governed by Kirchhoff's Voltage Law: V=Eb+IaRaV = E_b + I_a R_aV=Eb​+Ia​Ra​. Since IaRa>0I_a R_a > 0Ia​Ra​>0 under normal operating conditions, EbE_bEb​ must be strictly less than VVV.

📌 Key Points
  • ▸

    Back EMF is proportional to speed and flux (Eb∝ΦNE_b \propto \Phi NEb​∝ΦN).

  • ▸

    At standstill (starting), N=0N = 0N=0, so Eb=0E_b = 0Eb​=0, leading to high starting current unless controlled.

  • ▸

    If Eb=VE_b = VEb​=V, the motor would draw zero current and perform no work.

  • ▸

    If Eb>VE_b > VEb​>V, the device acts as a generator, not a motor.

✅ Advantages
  • ▸

    Provides self-regulation of armature current based on mechanical load.

  • ▸

    Limits the current drawn from the supply to a safe level during operation.

❌ Disadvantages / Limitations
  • ▸

    High starting current is possible due to Eb=0E_b = 0Eb​=0 at start.

  • ▸

    Requires external starting resistors or starters to prevent winding damage.

🛠️ Applications / Uses
  • ▸

    Industrial variable speed drives.

  • ▸

    Electric traction systems.

  • ▸

    Battery-operated small motor devices.

📄 Additional Information
  • ▸

    The back EMF is often termed 'Counter EMF' because it opposes the applied voltage source.

  • ▸

    Option B is incorrect because if Eb>VE_b > VEb​>V, the machine enters regenerative braking mode (generating).

  • ▸

    Option C is incorrect because it would result in zero current, preventing the production of electromagnetic torque.

📊 Diagram / Illustration
DC Motor Voltage BalanceE♭ = V - Iₐ Rₐ
Eb<VE_b < VEb​<V (since IaRa>0I_a R_a > 0Ia​Ra​>0)
✅

A is correct — The counter EMF EbE_bEb​ is always less than the applied terminal voltage VVV because a portion of the voltage is consumed by the armature ohmic drop (IaRaI_a R_aIa​Ra​).

Core Concepts Used
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Back EMF (Counter EMF) Lenz's Law DC Motor Armature Circuit
💡 EXAM TIP

Remember: EbE_bEb​ is directly proportional to speed NNN. At no-load, NNN reaches its maximum, causing EbE_bEb​ to be nearly equal to VVV, resulting in very low armature current.

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