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Examoogle • User • info@examoogle.com • EE-2024-8821
Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
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Each of G, J, M, O, R, S and T has an exam on a different day of a week, starting from Monday and ending on Sunday of the same week.
Only three people have exams between O and S. Only three people have exams between G and J. T has an exam on some day before R and on some day after M. Only J has an exam after S.
Who has an exam on Thursday?
G
T
O
M
T
Fix the anchor point: 'Only J has an exam after S' means S is Saturday and J is Sunday. Then use the gaps to place G, M, O, R, and T.
Fix the anchor point: 'Only J has an exam after S' means S is Saturday and J is Sunday. Then use the gaps to place G, M, O, R, and T.
Fixing the Days
There are 7 days: Mon, Tue, Wed, Thu, Fri, Sat, Sun. 'Only J has an exam after S' implies S is Saturday and J is Sunday.
Placing G and J
'Only three people have exams between G and J'. If J is Sunday (Day7), then G must be Wednesday (Day3). However, there are 3 between them: G(3), 4, 5, 6, J(7). This fits.
Placing O and S
'Only three people have exams between O and S'. With S at Saturday (Day6), O must be Tuesday (Day2). Wait, let's re-verify: S=6, O=2. Gap is (3,4,5) = 3 people. Correct.
Placing T, R, M
Remaining days: Mon(1), Thu(4), Fri(5). Condition: T is before R and after M. SoM=1, T=4, R=5. Result: T is Thursday.
A: G has an exam on Wednesday. C: O has an exam on Tuesday. D: M has an exam on Monday.
B is correct because the sequence M(Mon), O(Tue), G(Wed), T(Thu), R(Fri), S(Sat), J(Sun) satisfies all conditions.
In scheduling puzzles, always identify the 'boundary' condition (like 'Only J is after S') first to freeze the timeline, then fill in the gaps.