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Five friends - D, R, S, T, and K - went to a city on the 2nd, 4th, 6th, 8th, and 10th of August. R went on the 4th. K went on the 10th. T did not go on the 2nd. T went before D. S did not go immediately after R. Who went on the 8th?
S
K
T
D
D
Map fixed variables first (R=4, K=10) and then place remaining variables (T, D, S) by testing the sequence constraints on the remaining dates (2, 6, 8).
Map fixed variables first (R=4, K=10) and then place remaining variables (T, D, S) by testing the sequence constraints on the remaining dates (2, 6, 8).
Fix the given positions
We have dates 2, 4, 6, 8, 10. Given R=4 and K=10. Remaining people are D, S, and T for dates 2, 6, 8.
Apply constraints
T is not on 2, so T must be on 6 or 8. Since T is before D, T cannot be on 8. Thus, T must be on 6. This leaves D for date 2 or 8. If D is on 2, S must be on 8; if D is on 8, S must be on 2.
Verify S not immediately after R
R is on 4. If S were on 6, it would violate the rule. With T on 6, this is satisfied. If S is on 2, it is before R, so it is valid. If S is on 8, it is not immediately after 4. Testing D=8 and S=2: Dates are 2=S, 4=R, 6=T, 8=D, 10=K. This satisfies all conditions.
A: S went on the 2nd. B: K went on the 10th. C: T went on the 6th.
D is correct because based on the constraints (T not on 2, T before D, R=4, K=10), the only valid sequence is 2-S, 4-R, 6-T, 8-D, 10-K, placing D on the 8th.
When solving scheduling puzzles, always prioritize placing the entities with negative constraints (like 'T not on 2') last to narrow down the options quickly.
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