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For a given ferrite material operating in linear mode, B = 0.05 T and μr = 50. The magnetization M is
39,000 A/m
1000 A/m
16,000 A/m
2500 A/m
39,000 A/m
Given: Magnetic flux density B = 0.05 T, relative permeability μ_r = 50, permeability of free space μ_0 = 4π × 10°-7 H/m
Magnetic flux density B = 0.05 T, relative permeability μ_r = 50, permeability of free space μ_0 = 4π × 10°-7 H/m
M=(μ0μrμr−1)B
Calculate the Magnetic Field Intensity (H)
Magnetic flux density is related to magnetic field intensity by B=μ0μrH. Rearranging for H: H=μ0μrB
H=4π×10°−7×500.05
Determine H value
Substituting the values: H=200π×10°−70.05=6.283×10°−50.05≈795.77 A/m.
H≈795.77 A/m
Calculate Magnetization (M)
Magnetization M is given by M=χmH, where χm=μr−1. So, M=(μr−1)H.
M=(50−1)×795.77=49×795.77
Final Computation
Multiplying the values: M=49×795.77≈38992.73 A/m, which rounds to approximately 39,000 A/m.
M≈39,000 A/m
A is correct because the calculated magnetization M using the relation M = (μ_r - 1)H results in approximately 39,000 A/m.
In electromagnetics, remember that B, H, and M are strictly linked by the material property μ_r; always check if the material is paramagnetic, diamagnetic, or ferromagnetic to determine the validity of the linear approximation.