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For a given soil mass, the void ratio is 0.60, water content is 18% and specific gravity of the soil particles is 2.6. The degree of saturation of the soil is
30%
50%
78%
82.50%
78%
Given: Void ratio e = 0.60, water content w = 18% (0.18), and specific gravity Gs = 2.6.
Void ratio e = 0.60, water content w = 18% (0.18), and specific gravity Gs = 2.6.
S├Чe=w├ЧGsтАЛ
Identify given parameters
List the given geotechnical properties: void ratio e=0.60, water content w=0.18, and specific gravity of solids GsтАЛ=2.6.
e=0.60,w=0.18,GsтАЛ=2.6
Select the governing relation
Use the fundamental phase relationship in soil mechanics that links saturation, void ratio, water content, and specific gravity.
S├Чe=w├ЧGsтАЛ
Substitute values
Substitute the known values into the equation to solve for the degree of saturation S.
S├Ч0.60=0.18├Ч2.6
Calculate the result
Perform the arithmetic: S=0.600.18├Ч2.6тАЛ=0.600.468тАЛ=0.78. Convert the decimal to percentage by multiplying by 100.
S=0.78├Ч100=78%
C is correct because the degree of saturation calculated using the relation Se=wGsтАЛ results in 78%.
This relationship Se=wGsтАЛ is the most critical equation in soil mechanics; it is frequently used to determine the dry unit weight of soil when combined with the bulk unit weight formula.