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For a given soil mass, the void ratio is 0.60, water content is 18% and specific gravity of the soil particles is 2.6. The degree of saturation of the soil is
30 %
50 %
78 %
82.50 %
78 %
Given: Void ratio e = 0.60, water content w = 18% (0.18), and specific gravity Gs = 2.6.
Void ratio e = 0.60, water content w = 18% (0.18), and specific gravity Gs = 2.6.
S×e=w×Gs
Identify given parameters
List the given geotechnical properties: void ratio e=0.60, water content w=0.18, and specific gravity of solids Gs=2.6.
e=0.60,w=0.18,Gs=2.6
Select the governing relation
Use the fundamental phase relationship in soil mechanics that links saturation, void ratio, water content, and specific gravity.
S×e=w×Gs
Substitute values
Substitute the known values into the equation to solve for the degree of saturation S.
S×0.60=0.18×2.6
Calculate the result
Perform the arithmetic: S=0.600.18×2.6=0.600.468=0.78. Convert the decimal to percentage by multiplying by 100.
S=0.78×100=78%
C is correct because the degree of saturation calculated using the relation Se=wGs results in 78%.
This relationship Se=wGs is the most critical equation in soil mechanics; it is frequently used to determine the dry unit weight of soil when combined with the bulk unit weight formula.