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For single phase overhead line having solid conductors of diameter 1 cm spaced 60 cm between centers, the inductance in mH/km is
$0.05 + 0.2 \log 60$
$0.2 \log 60$
$0.05 + 0.2 \log(60/0.5)$
$0.2 \log(60/0.5)$
$0.05 + 0.2 \log(60/0.5)$
Given: Diameter of conductor d = 1 cm, Radius r = 0.5 cm, Spacing between centers D = 60 cm
Diameter of conductor d = 1 cm, Radius r = 0.5 cm, Spacing between centers D = 60 cm
L=0.05+0.2ln(rтА▓DтАЛ)┬аmH/km
Identify given parameters
The conductor diameter is d=1 cm, so the radius r=d/2=0.5 cm ┬╖ The distance between centers is D=60 cm.
r=0.5┬аcm,D=60┬аcm
Use the Inductance formula
The loop inductance for a single-phase transmission line per kilometer is given by L=0.05+0.2ln(D/rтА▓), where rтА▓=reтИТ1/4тЙИ0.7788r. However, in standard textbook notation for this specific problem type, the expression is represented as $0.05 + 0.2 \log(D/r)$.
L=0.05+0.2log(rDтАЛ)
Substitute values
Substitute D=60 and r=0.5 into the equation.
L=0.05+0.2log(0.560тАЛ)
C is correct because the inductance formula for a single-phase line is L=0.05+0.2log(D/r), which results in $0.05 + 0.2 \log(60/0.5)$ mH/km.
This concept is fundamental for calculating the impedance of transmission lines, which is used in load flow studies and fault analysis.