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MathematicsRatio & Proportion
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If a:b=5:2a: b = 5: 2a:b=5:2, then (a+b):(aтИТb)=?(a + b): (a - b) =? (a+b):(aтИТb)=?

A

7: 3

B

3: 7

C

5: 2

D

2: 5

Correct Answer

ЁЯУР MA тАв Math Ratio Substitution MethodMathematicsRatio & Proportion
Option A

7: 3

Quick Summary:

Given: The ratio of two variables a and b is given as a: b = 5: 2.

ЁЯУРMAMath SolutionRatio Substitution Method
ЁЯУЛ Given

The ratio of two variables a and b is given as a: b = 5: 2.

ЁЯФв Formula Used

a+baтИТb=k(aratio)+k(bratio)k(aratio)тИТk(bratio)\frac{a+b}{a-b} = \frac{k(a_{ratio}) + k(b_{ratio})}{k(a_{ratio}) - k(b_{ratio})}aтИТba+bтАЛ=k(aratioтАЛ)тИТk(bratioтАЛ)k(aratioтАЛ)+k(bratioтАЛ)тАЛ

тЪб Exam Hall Shortcut / Speed Trick

Since the ratio is given, directly substitute a = 5 and b = 2 into the expression. The constant k cancels out, so (5+2) / (5-2) gives the result instantly.

тЪая╕П Common Student Trap / Pitfall

Students often mistakenly calculate (a-b) / (a+b) or invert the values of a and b, resulting in an incorrect ratio like 3:7 instead of 7:3.

ЁЯУК Diagram / Illustration
Ratio & Proportion: Substitution Method 1 Given Ratio a : b = 5 : 2 тЯ╣ Assume a = 5k, b = 2k 2 Substitute Values (a + b) / (a - b) = (5k + 2k) / (5k - 2k) 3 Simplify Expression = 7k / 3k = 7 / 3 4 Final Result (a + b) : (a - b) = 7 : 3 Correct Option: A) 7 : 3
ЁЯФв Step-by-Step Solution
1

Define the ratio variables

Assume a=5ka = 5ka=5k and b=2kb = 2kb=2k, where k is a non-zero constant.

a=5k,b=2ka = 5k, \quad b = 2ka=5k,b=2k

2

Substitute into the required expression

Substitute the values of a and b into the expression a+baтИТb\frac{a+b}{a-b}aтИТba+bтАЛ.

a+baтИТb=5k+2k5kтИТ2k\frac{a+b}{a-b} = \frac{5k + 2k}{5k - 2k}aтИТba+bтАЛ=5kтИТ2k5k+2kтАЛ

3

Simplify the expression

Combine the terms in the numerator and denominator and cancel out the common constant k.

7k3k=73\frac{7k}{3k} = \frac{7}{3}3k7kтАЛ=37тАЛ

тЬЕ

A is correct because substituting a = 5 and b = 2 into the expression results in 7: 3.

Core Concepts Used
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Ratio and Proportion Algebraic Substitution Constant of Proportionality
ЁЯТб EXAM TIP

This substitution method is the foundation for solving complex problems in Mixture and Alligation, where ratios are frequently converted into absolute values using a constant factor.

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