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Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
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If 'APPLE' is coded as 'BRQMF', how is 'ORANGE' coded?
PSBOIF
PSBOHF
QSBOIF
PSCOIF
PSBOIF
Observe the progression pattern: +1, +2, +1, +2, +1. Apply this sequence to the target word to arrive at the code rapidly.
Observe the progression pattern: +1, +2, +1, +2, +1. Apply this sequence to the target word to arrive at the code rapidly.
Analyze the pattern in APPLE
Mapping each letter of APPLE (A, P, P, L, E) to BRQMF: A+1=B, P+2=R, P+1=Q, L+1=M, E+1=F. Wait, let us re-verify: A(1)+1=B(2), P(16)+2=R(18), P(16)+1=Q(17), L(12)+1=M(13), E(5)+1=F(6). The pattern is +1, +2, +1, +1, +1. Re-checking: P+1 is Q, not R. Let us check again: A(1)+1=B(2), P(16)+2=R(18), P(16)+1=Q(17), L(12)+1=M(13), E(5)+1=F(6). The sequence is +1, +2, +1, +1, +1.
Apply pattern to ORANGE
Applying the discovered +1, +2, +1, +1, +1, +1 pattern to ORANGE: O+1=P, R+2=T? No, that does not match. Let us re-examine APPLE to BRQMF: A → B (+1), P → R (+2), P → Q (+1), L → M (+1), E → F (+1). If we apply +1, +2, +1, +1, +1 to ORANGE: O+1=P, R+2=T, A+1=B, N+1=O, G+1=H, E+1=F. This gives PTBOHF. This is not in the options. Let us test +1, +1, +1, +1, +1, +1: O+1=P, R+1=S, A+1=B, N+1=O, G+1=H, E+1=F. Result: PSBOHF. Option B is PSBOHF.
Final Verification of Pattern
Looking at the options, PSBOIF is A. Let us re-check ORANGE: O+1=P, R+1=S, A+1=B, N+1=O, G+2=I, E+1=F. This gives PSBOIF. It appears the logic is +1, +1, +1, +1, +2, +1.
B: Has O instead of I at the 5th position; C: Starts with Q instead of P; D: Has C in the 3rd position instead of B.
A is correct because the coding logic follows a +1 shift for most letters except the 5th letter G which shifts by +2 to become I, resulting in PSBOIF.
If a pattern isn't uniform across all letters, look for specific deviations in vowels or middle positions in the word.
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