Join 60,000+ competitive exam aspirants
If sin╬╕тИТcos╬╕sin╬╕+cos╬╕тАЛ=3, then the value of tan╬╕ is:
2
3
4
1
2
Use the property of Componendo and Dividendo directly: if (x+y)/(x-y) = k, then x/y = (k+1)/(k-1). Here, sin ╬╕ / cos ╬╕ = (3+1)/(3-1) = 4/2 = 2.
The ratio of sum and difference of sin and cos is given as: (sin ╬╕ + cos ╬╕) / (sin ╬╕ - cos ╬╕) = 3
aтИТba+bтАЛ=dcтАЛтЯ╣baтАЛ=cтИТdc+dтАЛ
Use the property of Componendo and Dividendo directly: if (x+y)/(x-y) = k, then x/y = (k+1)/(k-1). Here, sin ╬╕ / cos ╬╕ = (3+1)/(3-1) = 4/2 = 2.
Students often try to cross-multiply and solve for ╬╕ individually instead of identifying the tan ╬╕ ratio directly, leading to algebraic errors.
Apply Componendo and Dividendo
Given the equation sin╬╕тИТcos╬╕sin╬╕+cos╬╕тАЛ=13тАЛ, we apply the rule aтИТba+bтАЛ=cтИТdc+dтАЛ where a=sin╬╕ and b=cos╬╕.
(sin╬╕+cos╬╕)тИТ(sin╬╕тИТcos╬╕)(sin╬╕+cos╬╕)+(sin╬╕тИТcos╬╕)тАЛ=3тИТ13+1тАЛ
Simplify the fractions
After simplifying the numerator and denominator, the terms cos╬╕ and sin╬╕ cancel out respectively.
2cos╬╕2sin╬╕тАЛ=24тАЛ
Final calculation
Since cos╬╕sin╬╕тАЛ=tan╬╕, we divide the constants to reach the result.
tan╬╕=2
A is correct because applying the Componendo and Dividendo rule leads directly to tan╬╕=2.
This property is frequently tested in 'Ratio and Proportion' chapters as well; identifying it saves time in competitive exams for problems involving linear combinations of functions.