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If P(A) = 0.4, P(B) = 0.5, and P(A тИй B) = 0.2, what is P(A тИк B)?
0.7
0.9
0.1
0.6
0.7
The probability of the union of two events A and B is determined using the addition theorem of probability, which states that P(A union B) equals P(A) plus P(B) minus P(A intersection B). Substituting the given values yields 0.4 plus 0.5 minus 0.2, resulting in 0.7.
The probability of the union of two events A and B is determined using the addition theorem of probability, which states that P(A union B) equals P(A) plus P(B) minus P(A intersection B). Substituting the given values yields 0.4 plus 0.5 minus 0.2, resulting in 0.7.
In quantitative aptitude sections of Indian competitive examinations like RRB and SSC, probability based on set operations forms a permanent core component of the mathematics syllabus.
The addition theorem is fundamental for solving problems involving compound probability.
The probability of any standard event always ranges strictly from 0 to 1.
For mutually exclusive events, the intersection term becomes zero.
Option B (0.9) is incorrect because it represents a direct addition without accounting for the overlapping intersection.
Option C (0.1) arises from an incorrect mathematical operation or sign reversal.
Option D (0.6) is a distractor derived from incorrect subtraction of terms.
A is correct тАФ The value of P(A union B) is 0.7, calculated using the standard addition theorem of probability.
Mastering probability fundamentals aids directly in solving advanced statistics and data interpretation questions frequently tested in RRB Technician exams.