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ElectricalMachine
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If the radius of the current carrying conductor increases, what is the effect on the force

A

increases

B

decreases

C

remain the same

D

become zero

Correct Answer

тЪЩя╕П TE тАв Technical Concept & PrincipleElectricalMachine
Option C

remain the same

Quick Summary:

The magnetic force on a current-carrying straight conductor in a uniform magnetic field depends solely on the magnitude of current, the length of the conductor inside the field, the external magnetic flux density, and the angle between the conductor and the magnetic field. It is completely independent of the cross-sectional radius or physical thickness of the conductor. Therefore, increasing the radius of the conductor leaves the net magnetic force unchanged.

тЪЩя╕ПTETechnical SolutionConcept & Principle
ЁЯТб Explanation

The magnetic force on a current-carrying straight conductor in a uniform magnetic field depends solely on the magnitude of current, the length of the conductor inside the field, the external magnetic flux density, and the angle between the conductor and the magnetic field. It is completely independent of the cross-sectional radius or physical thickness of the conductor. Therefore, increasing the radius of the conductor leaves the net magnetic force unchanged.

ЁЯФв Key Formulas

F=ILBsinтБб╬╕F = I L B \sin\thetaF=ILBsin╬╕ тАФ Magnetic force on a straight current-carrying conductor

I=nqAvdI = n q A v_dI=nqAvdтАЛ тАФ Relationship between current, cross-sectional area AAA, and drift velocity vdv_dvdтАЛ

тЪЩя╕П Working Principle

When charges move through a conductor immersed in an external magnetic field, each individual moving charge experiences a microscopic Lorentz force. The total macroscopic magnetic force exerted on the conductor is the vector sum of these individual microscopic forces over the entire active volume. Because the total current III represents the total charge flowing per unit time across the cross-section (I=nqAvdI = n q A v_dI=nqAvdтАЛ), any change in cross-sectional area AAA due to a altered radius changes the drift velocity vdv_dvdтАЛ inversely, keeping the total macroscopic product I=nqAvdI = n q A v_dI=nqAvdтАЛ and resulting force FFF constant.

ЁЯУМ Key Points
  • тЦ╕

    The force FFF is directly proportional to current III, conductor length LLL, and magnetic flux density BBB.

  • тЦ╕

    Conductor radius or cross-sectional area AAA does not feature in the standard magnetic force equation F=ILBsinтБб╬╕F = I L B \sin\thetaF=ILBsin╬╕.

  • тЦ╕

    Increasing conductor radius decreases resistance and drift velocity for a given current, but the total Lorentz force on the entire current remains unchanged.

ЁЯУД Additional Information
  • тЦ╕

    Option A (increases) is incorrect because force does not depend directly or inversely on cross-sectional dimensions.

  • тЦ╕

    Option B (decreases) is incorrect as force relies on net charge flow rate III, not the individual wire radius.

  • тЦ╕

    Option D (become zero) is incorrect because force becomes zero only if I=0I = 0I=0, B=0B = 0B=0, L=0L = 0L=0, or ╬╕=0┬░/180┬░\theta = 0┬░/180┬░╬╕=0┬░/180┬░.

ЁЯУК Diagram / Illustration
Magnetic Force on ConductorF = I ├Ч L ├Ч B ├Ч sin(╬╕)Independent of Conductor Radius (r)Variables: I = Current, L = Length, B = Field, ╬╕ = Angle
тЬЕ

C is correct тАФ The magnetic force depends on current, length, and magnetic field strength, making it independent of conductor radius.

Core Concepts Used
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Lorentz Force Current-Carrying Conductor in Magnetic Field Drift Velocity and Current Density
ЁЯТб EXAM TIP

In competitive exams, always check whether the parameter being modified (like conductor radius) explicitly appears in the core formula (F=ILBsinтБб╬╕F = ILB\sin\thetaF=ILBsin╬╕) before selecting an option.

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