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ElectricalPower System
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If the supply has frequency f Hz then what would be the frequency of intantaneous power?

A

f

B

x f

C

f / 2

D

f x f

Correct Answer

тЪЩя╕П TE тАв Technical Concept & PrincipleElectricalPower System
Option B

x f

Quick Summary:

The instantaneous power in an AC circuit containing resistance and reactance oscillates at a frequency that is exactly double the supply frequency. This occurs because the product of voltage (v(t)=VmsinтБб(╧Йt)v(t) = V_m \sin(\omega t)v(t)=VmтАЛsin(╧Йt)) and current (i(t)=ImsinтБб(╧ЙtтИТ╧Х)i(t) = I_m \sin(\omega t - \phi)i(t)=ImтАЛsin(╧ЙtтИТ╧Х)) generates a component containing the term sinтБб(╧Йt)sinтБб(╧ЙtтИТ╧Х)\sin(\omega t)\sin(\omega t - \phi)sin(╧Йt)sin(╧ЙtтИТ╧Х), which expands into a term involving 2╧Йt2\omega t2╧Йt.

тЪЩя╕ПTETechnical SolutionConcept & Principle
ЁЯТб Explanation

The instantaneous power in an AC circuit containing resistance and reactance oscillates at a frequency that is exactly double the supply frequency. This occurs because the product of voltage (v(t)=VmsinтБб(╧Йt)v(t) = V_m \sin(\omega t)v(t)=VmтАЛsin(╧Йt)) and current (i(t)=ImsinтБб(╧ЙtтИТ╧Х)i(t) = I_m \sin(\omega t - \phi)i(t)=ImтАЛsin(╧ЙtтИТ╧Х)) generates a component containing the term sinтБб(╧Йt)sinтБб(╧ЙtтИТ╧Х)\sin(\omega t)\sin(\omega t - \phi)sin(╧Йt)sin(╧ЙtтИТ╧Х), which expands into a term involving 2╧Йt2\omega t2╧Йt.

ЁЯФв Key Formulas

p(t)=VIcosтБб(╧Х)тИТVIcosтБб(2╧ЙtтИТ╧Х)p(t) = VI \cos(\phi) - VI \cos(2\omega t - \phi)p(t)=VIcos(╧Х)тИТVIcos(2╧ЙtтИТ╧Х) тАФ Instantaneous power expression

fp=2ff_p = 2ffpтАЛ=2f тАФ Frequency of power relative to supply frequency

тЪЩя╕П Working Principle

In an AC circuit, p(t)=v(t)cdoti(t)p(t) = v(t) cdot i(t)p(t)=v(t)cdoti(t). Using the trigonometric identity sinтБб(A)sinтБб(B)=12[cosтБб(AтИТB)тИТcosтБб(A+B)]\sin(A)\sin(B) = \frac{1}{2}[\cos(A-B) - \cos(A+B)]sin(A)sin(B)=21тАЛ[cos(AтИТB)тИТcos(A+B)], the product results in a constant term and a time-varying term that fluctuates at an angular frequency of 2╧Й2\omega2╧Й. Since ╧Й=2╧Аf\omega = 2\pi f╧Й=2╧Аf, the frequency of power becomes 2f2f2f, representing two power cycles for every one cycle of voltage/current.

ЁЯУМ Key Points
  • тЦ╕

    The instantaneous power consists of a constant average component and an oscillating component.

  • тЦ╕

    The oscillating component frequency is 2f2f2f because of the product of two sinusoidal functions of frequency fff.

  • тЦ╕

    In purely resistive circuits, the power never becomes negative but oscillates between 000 and 2VmIm2V_m I_m2VmтАЛImтАЛ at frequency 2f2f2f.

тЬЕ Advantages
  • тЦ╕

    Useful for calculating instantaneous torque in electric motors.

  • тЦ╕

    Essential for analyzing vibration and ripple in power electronic converters.

ЁЯЫая╕П Applications / Uses
  • тЦ╕

    AC motor torque ripple analysis

  • тЦ╕

    Power quality and harmonic analysis

  • тЦ╕

    Rectifier circuit design

ЁЯУД Additional Information
  • тЦ╕

    The constant term represents the real (active) power, while the oscillating term represents the alternating power flow.

  • тЦ╕

    Option A is incorrect as it implies power frequency equals supply frequency. Option C is incorrect as it would imply power frequency is slower than voltage, which is physically impossible in linear AC systems.

ЁЯУК Diagram / Illustration
Power Frequency RelationVoltage (f)Power (2f)
тЬЕ

B is correct тАФ The frequency of instantaneous power in an AC circuit is 2f2f2f, which is twice the supply frequency.

Core Concepts Used
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Instantaneous Power AC Circuit Theory Trigonometric Identities
ЁЯТб EXAM TIP

Always remember that whenever two signals of frequency fff are multiplied, the resultant frequency is 2f2f2f due to product-to-sum trigonometric identities.

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