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CivilAdvanced Survey
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If the value of length of the chord is given as 5.236 m and the radius of the curve as 100m, find the tangential angle using Rankine’s method.

A

A) 120°120°120°

B

B) 1°30′1°30'1°30′

C

C) 130′130'130′

D

D) 1°20′1°20'1°20′

Correct Answer

⚙️ TE • Technical Concept & PrincipleCivilAdvanced Survey
Option B

1°30′1°30'1°30′

Quick Summary:

Rankine's method (method of tangential angles) is used to set out circular curves using a transit theodolite and a tape. The tangential angle for any chord is given by the formula δ=1718.9×CR\delta = 1718.9 \times \frac{C}{R}δ=1718.9×RC​ minutes, where CCC is the length of the chord and RRR is the radius of the curve. Substituting C=5.236 mC = 5.236\text{ m}C=5.236 m and R=100 mR = 100\text{ m}R=100 m gives δ=90′=1°30′\delta = 90' = 1°30'δ=90′=1°30′, making Option B the correct answer.

⚙️TETechnical SolutionConcept & Principle
💡 Explanation

Rankine's method (method of tangential angles) is used to set out circular curves using a transit theodolite and a tape. The tangential angle for any chord is given by the formula δ=1718.9×CR\delta = 1718.9 \times \frac{C}{R}δ=1718.9×RC​ minutes, where CCC is the length of the chord and RRR is the radius of the curve. Substituting C=5.236 mC = 5.236\text{ m}C=5.236 m and R=100 mR = 100\text{ m}R=100 m gives δ=90′=1°30′\delta = 90' = 1°30'δ=90′=1°30′, making Option B the correct answer.

🔢 Key Formulas

δ=1718.9×CR minutes\delta = 1718.9 \times \frac{C}{R}\text{ minutes}δ=1718.9×RC​ minutes — Tangential angle for a chord of length CCC and radius RRR

Δn=∑i=1nδi\Delta_n = \sum_{i=1}^{n} \delta_iΔn​=∑i=1n​δi​ — Total deflection angle for point nnn

⚙️ Working Principle

In Rankine's deflection angle method, the deflection angle to any point on the curve is equal to half the angle subtended by the arc at the center. For small chord lengths, the arc length is approximated by the chord length CCC. The tangential angle δ\deltaδ in minutes is derived from the relation \delta = \frac{C}{2R} \times \frac{180°{\pi} \times 60' \approx 1718.873 \times \frac{C}{R} minutes.

📌 Key Points
  • ▸

    Rankine's method is suitable for setting out simple circular curves when the curve is long and high precision is required.

  • ▸

    The total deflection angle to any point on the curve is equal to the sum of the tangential angles of all preceding sub-chords.

  • ▸

    The chord length CCC and radius RRR must be measured in the same units (meters).

✅ Advantages
  • ▸

    Highly accurate and suitable for long circular curves in field surveying.

  • ▸

    Linear measurements are made with a tape while angular measurements are taken with a theodolite.

❌ Disadvantages / Limitations
  • ▸

    Slower compared to offset methods due to continuous sight setting and transit usage.

  • ▸

    Accumulation of errors can occur if individual chord measurements or tangential angle settings are inaccurate.

🛠️ Applications / Uses
  • ▸

    Setting out circular curves for highways and railway track alignments.

  • ▸

    Precision alignment where offset methods are impractical due to terrain obstacles.

📄 Additional Information
  • ▸

    Calculation: δ=1718.9×5.236100=89.999... minutes≈90′=1°30′\delta = 1718.9 \times \frac{5.236}{100} = 89.999...\text{ minutes} \approx 90' = 1°30'δ=1718.9×1005.236​=89.999... minutes≈90′=1°30′.

  • ▸

    Option A (120°) represents an incorrect large degree conversion.

  • ▸

    Option C (130ˈ) uses an incorrect arithmetic evaluation of 1718.9×0.052361718.9 \times 0.052361718.9×0.05236.

  • ▸

    Option D (1° 20ˈ) corresponds to 80′80'80′ which is a computational error.

📊 Diagram / Illustration
Rankine's Tangential Angle Formulaδ = ( C / 2R ) × ( 180° / π ) × 60'1718.9 × CRδ = 1718.9 × (5.236 / 100) = 90' = 1° 30'
✅

B is correct — Using Rankine's formula δ=1718.9×5.236100=90′\delta = 1718.9 \times \frac{5.236}{100} = 90'δ=1718.9×1005.236​=90′, which equals 1°30′1°30'1°30′.

Core Concepts Used
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Rankine's Method of Deflection Angles Simple Circular Curves Tangential Angle and Chord Length Relationship
💡 EXAM TIP

Remember that 1°=60′1°= 60'1°=60′. In competitive exams, questions on Rankine's method frequently expect the result in degrees and minutes, so always divide the calculated minutes by 60 to convert to degrees.

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