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If three cards are drawn one by one randomly from a pack of 52 cards, then what is the probability that three of them are jack?
55253тАЛ
55251тАЛ
5554тАЛ
5523тАЛ
55251тАЛ
Use the product of probabilities for successive dependent events: 524тАЛ├Ч513тАЛ├Ч502тАЛ=131тАЛ├Ч171тАЛ├Ч251тАЛ=55251тАЛ.
A pack of 52 cards contains 4 jacks. Three cards are drawn one by one without replacement.
P=524тАЛ├Ч513тАЛ├Ч502тАЛ
Use the product of probabilities for successive dependent events: 524тАЛ├Ч513тАЛ├Ч502тАЛ=131тАЛ├Ч171тАЛ├Ч251тАЛ=55251тАЛ.
Students often treat drawing cards as independent events with replacement, leading them to use 524тАЛ├Ч524тАЛ├Ч524тАЛ instead of accounting for the reduced pool of cards.
Calculate probability of first jack
There are 4 jacks in a deck of 52 cards, so the probability of picking the first jack is 4/52.
P1тАЛ=524тАЛ=131тАЛ
Calculate probability of second jack
After one jack is drawn, there are 3 jacks remaining in a pool of 51 cards.
P2тАЛ=513тАЛ=171тАЛ
Calculate probability of third jack
After two jacks are drawn, there are 2 jacks remaining in a pool of 50 cards.
P3тАЛ=502тАЛ=251тАЛ
Calculate total probability
Since these are dependent events occurring in sequence, multiply the probabilities.
P=131тАЛ├Ч171тАЛ├Ч251тАЛ=55251тАЛ
B is correct because the product of the probabilities of drawing three jacks consecutively without replacement is 1/5525.
This logic is identical to sampling without replacement in statistics; always subtract both the numerator and the denominator counts for successive draws.