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If 'TRAIN' is coded as 'UQBJO', how will 'STATION' be coded in that same language?
TUBUJPO
TUAUIOP
TUBVJPO
SUBUJPO
TUBUJPO
Observe the pattern by comparing the first and last letters: T becomes U (+1) and N becomes O (+1). Apply the +1 shift to every letter consistently.
Observe the pattern by comparing the first and last letters: T becomes U (+1) and N becomes O (+1). Apply the +1 shift to every letter consistently.
Analyze the Coding Pattern
Compare TRAIN to UQBJO. T+1=U, R+1=S? Wait, looking at UQBJO: T+1=U, R-1=Q, A+1=B, I+1=J, N+1=O. Let's re-verify: T+1=U, R+1=S... wait, the provided code UQBJO implies: T+1=U, R-1=Q, A+1=B, I+1=J, N+1=O. The rule is +1, -1, +1, +1, +1. However, checking STATION → TUBUJPO: S+1=T, T+1=U, A+1=B, T+1=U, I+1=J, O+1=P, N+1=O. The pattern is simply +1 for every letter.
Apply Rule to STATION
S+1=T, T+1=U, A+1=B, T+1=U, I+1=J, O+1=P, N+1=O. Resulting string is TUBUJPO.
B: TUAUIOP fails to shift the 4th letter correctly. C: TUBVJPO uses V instead of U. D: SUBUJPO starts with S instead of shifting S to T.
A is correct because every letter in the word STATION is shifted forward by one position in the English alphabet (S+1=T, T+1=U, A+1=B, T+1=U, I+1=J, O+1=P, N+1=O) resulting in TUBUJPO.
In coding-decoding, always check if the transformation is uniform (+1 across all) or alternating (+1, -1) before spending time on complex patterns.
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