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If x varies directly as y┬▓ and x = 12 when y = 2, find x when y = 5.
75
60
90
45
75
Use the ratio method: (x1тАЛ/x2тАЛ)=(y1тАЛ/y2тАЛ)2. Thus, 12/x2тАЛ=(2/5)2=4/25. Therefore, x2тАЛ=12├Ч(25/4)=75.
x varies directly as y squared, x = 12 when y = 2, find x when y = 5.
xтИЭy2тЯ╣y12тАЛx1тАЛтАЛ=y22тАЛx2тАЛтАЛ
Use the ratio method: (x1тАЛ/x2тАЛ)=(y1тАЛ/y2тАЛ)2. Thus, 12/x2тАЛ=(2/5)2=4/25. Therefore, x2тАЛ=12├Ч(25/4)=75.
Students often forget to square the variable y and simply set up a direct proportion like 12/2=x/5, which leads to the incorrect answer 30.
Establish the relationship
Since x varies directly as y2, we write x=ky2, where k is the constant of variation.
x=ky2
Find the constant k
Substitute the given values x=12 and y=2 to find k: 12=k├Ч22, which simplifies to 12=4k, hence k=3.
k=412тАЛ=3
Calculate the target value
Now substitute k=3 and y=5 into the original equation to find x: x=3├Ч52.
x=3├Ч25=75
A is correct because substituting y=5 into the derived relation x=3y2 yields x=75.
This concept of direct variation is foundational for Physics problems involving relationships like EтИЭv2 (Kinetic Energy) or FтИЭrтИТ2 (Inverse Square Law), where scaling factors allow for rapid mental calculation.