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ElectricalPower System
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If Y11oldY 11 o l dY11old is (1.018-j3.054) and admitance (2-j6) is added between bus 1 and 2 then new admitance of Y11newY 11 n e wY11new is

A

j3.44

B

223-j4.321

C

018-j9.054

D

3333-j2.2222

Correct Answer

тЪЩя╕П TE тАв Technical Concept & PrincipleElectricalPower System
Option C

018-j9.054

Quick Summary:

In a Y-bus matrix, the diagonal element YiiY_{ii}YiiтАЛ represents the sum of all admittances connected to bus iii. When a new admittance YijY_{ij}YijтАЛ is added between bus iii and bus jjj, it is added to the self-admittance YiiY_{ii}YiiтАЛ because the node iii is now connected to an additional branch.

тЪЩя╕ПTETechnical SolutionConcept & Principle
ЁЯТб Explanation

In a Y-bus matrix, the diagonal element YiiY_{ii}YiiтАЛ represents the sum of all admittances connected to bus iii. When a new admittance YijY_{ij}YijтАЛ is added between bus iii and bus jjj, it is added to the self-admittance YiiY_{ii}YiiтАЛ because the node iii is now connected to an additional branch.

ЁЯФв Key Formulas

Yii,new=Yii,old+YijY_{ii, new} = Y_{ii, old} + Y_{ij}Yii,newтАЛ=Yii,oldтАЛ+YijтАЛ тАФ Formula for updating self-admittance in Y-bus matrix

тЪЩя╕П Working Principle

The Y-bus matrix is formulated using nodal analysis ┬╖ The self-admittance YiiY_{ii}YiiтАЛ is defined as the sum of all admittances connected directly to bus iii. Adding a branch YijY_{ij}YijтАЛ increases the total admittance connected to bus iii, hence Yii,new=Yii,old+YijY_{ii, new} = Y_{ii, old} + Y_{ij}Yii,newтАЛ=Yii,oldтАЛ+YijтАЛ.

ЁЯУМ Key Points
  • тЦ╕

    Y-bus diagonal elements (YiiY_{ii}YiiтАЛ) represent the sum of all admittances connected to bus iii.

  • тЦ╕

    Adding an admittance between two nodes changes both the diagonal elements (YiiY_{ii}YiiтАЛ and YjjY_{jj}YjjтАЛ) and the off-diagonal elements (YijY_{ij}YijтАЛ and YjiY_{ji}YjiтАЛ).

  • тЦ╕

    Calculations are performed by adding complex numbers in rectangular form a+jba + jba+jb.

тЬЕ Advantages
  • тЦ╕

    Simplifies power flow analysis calculations.

  • тЦ╕

    Easily handles network modifications without recalculating the entire matrix.

тЭМ Disadvantages / Limitations
  • тЦ╕

    Requires complex number arithmetic which is prone to manual calculation errors.

  • тЦ╕

    Applicable only to linear network components.

ЁЯЫая╕П Applications / Uses
  • тЦ╕

    Power flow studies (Newton-Raphson, Gauss-Seidel).

  • тЦ╕

    Short circuit analysis and contingency studies.

ЁЯУД Additional Information
  • тЦ╕

    The calculation: (1.018+2)тИТj(3.054+6)=3.018тИТj9.054(1.018 + 2) - j(3.054 + 6) = 3.018 - j9.054(1.018+2)тИТj(3.054+6)=3.018тИТj9.054.

  • тЦ╕

    Option C is the only mathematically consistent result for the stated operation.

ЁЯУК Diagram / Illustration
Y-bus ModificationY_11, new = Y_11, old + YтВБтВВ(1.018 - j3.054) + (2 - j6)= 3.018 - j9.054
тЬЕ

C is correct тАФ Adding a shunt or series admittance YijY_{ij}YijтАЛ to bus 1 increases the diagonal element Y11Y_{11}Y11тАЛ of the Y-bus matrix by the value of that admittance.

Core Concepts Used
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Y-bus matrix formulation Nodal admittance method Complex number arithmetic
ЁЯТб EXAM TIP

Always verify if the admittance is added as a shunt or series element, though for Y-bus modification, both affect the diagonal element YiiY_{ii}YiiтАЛ identically.

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