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In a certain code language, A + B means ‘A is the son of B’, A – B means ‘A is the brother of B’, A x B means ‘A is the wife of B’, and A ÷ B means ‘A is the father of B’. Based on the above, how is L related to P if ‘L + M ÷ N x O – P’?
Brother’s wife’s father
Wife’s father
Wife’s brother
Brother’s wife’s brother
Brother’s wife’s brother
Break the expression into individual pairs: L+M (L is son of M), M÷N (M is father of N), N×O (N is wife of O), O-P (O is brother of P). Follow the chain from L down to P.
Break the expression into individual pairs: L+M (L is son of M), M÷N (M is father of N), N×O (N is wife of O), O-P (O is brother of P). Follow the chain from L down to P.
Analyze the expression segments
L + M: L is the son of M. M ÷ N: M is the father of N. N x O: N is the wife of O (implies M is father-in-law to O). O - P: O is the brother of P.
Establish the relationship tree
Since L is the son of M, and M is the father of N, L and N are siblings. N is the wife of O. O is the brother of P. Therefore, L is the brother of N. Since N is the wife of O, and O is the brother of P, L is the brother of N, N is the wife of O, and O is the brother of P. Thus, L is the brother-in-law (specifically, brother of the wife) of O. The relation being asked is how L is related to P. L is the brother of N, and N is the wife of O. Since O is the brother of P, L is the brother of P's brother's wife.
A: Brother's wife's father is incorrect because P is O's sibling, not a parent. B: Wife's father is incorrect as L is the same generation as N and O. C: Wife's brother is incorrect as that describes N to O, but L is related to P through this chain.
D is correct because based on the lineage L-M-N-O-P, L is the brother of N (N is the wife of O), and since O is the brother of P, L is the brother of the wife (N) of P's brother (O), which identifies him as the brother of P's brother's wife.
When solving blood relations with symbols, always draw a simple family tree using + for males and - for females to avoid confusion in multi-step relations.
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