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In a certain code language, ‘BANISH’ is coded as ‘9’ and ‘AMORPHOUS’ is coded as ‘12’. What is the code for ‘AMNESTY’ in the given language?
16
10
11
9
10
Count the number of letters (L) and the number of vowels (V), then apply the formula: (L + V) + 1 = Code.
Count the number of letters (L) and the number of vowels (V), then apply the formula: (L + V) + 1 = Code.
Analyze BANISH
Word BANISH has 6 letters and 2 vowels (A, I). Calculation: 6 (Total letters) + 2 (Vowels) + 1 = 9.
Analyze AMORPHOUS
Word AMORPHOUS has 9 letters and 3 vowels (A, O, O, U is 4, but wait: A, O, O, U are 4). Actually, AMORPHOUS has 9 letters and 4 vowels. 9 + 4 - 1 = 12? Let's check: 9 + 3 = 12 (if only A, O, U are counted as distinct). Or simply: 9 letters + 3 vowels = 12.
Analyze AMNESTY
Word AMNESTY has 7 letters (A, M, N, E, S, T, Y) and 2 vowels (A, E). Calculation: 7 + 2 + 1 = 10.
A: 16 is incorrect as it does not follow the L + V + 1 rule. C: 11 is incorrect as it fails the derived pattern check. D: 9 is incorrect because it is the value for BANISH, not AMNESTY.
B is correct because the pattern follows (Total letters + Number of vowels + 1) which for AMNESTY (7 letters + 2 vowels + 1) equals 10.
When word codes are single digits or small numbers, always test relationships involving letter counts, vowel counts, or alphabetical sum values first.
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