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In a certain code, 'ROAD' is written as 'URDG'. How is 'SWAN' written in that code?
VZDQ
VYDQ
VZEQ
UZDQ
VZDQ
Identify the positional shift constant for each letter by subtracting the original letter value from the target value; here, the pattern is +3, +5, +3, +3.
Identify the positional shift constant for each letter by subtracting the original letter value from the target value; here, the pattern is +3, +5, +3, +3.
Analyze the pattern in ROAD to URDG
Map letters to positions: R(18), O(15), A(1), D(4) and U(21), R(18), D(4), G(7). The shifts are: R+3=U, O+3=R, A+3=D, D+3=G. All letters follow a constant shift of +3.
Apply the identified pattern to SWAN
Apply +3 to each letter of SWAN: S(19)+3=22(V), W(23)+3=26(Z), A(1)+3=4(D), N(14)+3=17(Q). Result: VZDQ.
B: VYDQ uses +2 for the second letter; C: VZEQ uses incorrect arithmetic for the third and fourth letters; D: UZDQ uses incorrect logic for the first letter.
A is correct because the coding logic consistently applies a plus 3 shift to every letter in the word SWAN to derive VZDQ.
When encountering coding patterns, always write out the numerical positions (A=1, Z=26) to quickly spot arithmetic shifts between corresponding letters.
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