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In the equation of current, π° = (π½/πΏ)Γπππβ‘β .Β Β π½/πΏ = ___________Β &Β πππβ‘β = ___________
power factor angle & diameter of the circle
diameter of the circle & power factor angle
Impedance & power factor angle
power factor angle & Impedance
diameter of the circle & power factor angle
Quick Summary: Practice and solve "In the equation of current, π° = (π½/πΏ)Γπππβ‘β . π½/πΏ = ___________ & πππβ‘β = ___________..." for Electrical - Machine. The correct answer is Option B: diameter of the circle & power factor angle. Detailed step-by-step solution, conceptual clarity, and formulas on Examoogle.
Answer:
Option **(b) **