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In the word FREQUENCY, each consonant is changed to the letter immediately preceding it in the English alphabetical order and each vowel is changed to the letter immediately succeeding it in the English alphabetical order. How many vowels are present in the new group of letters thus formed?
1
2
3
0
1
Identify all vowels first; since vowels are shifted forward (+1) and consonants backward (-1), only a vowel shifted to another vowel would result in a vowel. Check E and U specifically.
Identify all vowels first; since vowels are shifted forward (+1) and consonants backward (-1), only a vowel shifted to another vowel would result in a vowel. Check E and U specifically.
Analyze the Word FREQUENCY
Break down the word: F(C), R(C), E(V), Q(C), U(V), E(V), N(C), C(C), Y(C). There are 3 vowels (E, U, E) and 6 consonants (F, R, Q, N, C, Y).
Apply Transformation Rules
Consonants move back by 1 (minus 1): F → E, R → Q, Q → P, N → M, C → B, Y → X. Vowels move forward by 1 (plus 1): E → F, U → V, E → F.
Evaluate New Group of Letters
The transformed letters are: E, Q, F, P, V, F, M, B, X. Listing these: E, Q, F, P, V, F, M, B, X. Comparing with A, E, I, O, U, we find no vowels in the resulting string.
A: Incorrect because there is not 1 vowel. B: Incorrect because there are not 2 vowels. C: Incorrect because there are not 3 vowels.
D is correct because the transformation of FREQUENCY results in the sequence E, Q, F, P, V, F, M, B, X, which contains zero vowels.
Always verify if a vowel shifting forward (+1) lands on another vowel (A, E, I, O, U). If the result is a consonant, the final count of vowels will be zero.