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Examoogle • User • info@examoogle.com • EE-2024-8821
Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
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ಒಬ್ಬ ವ್ಯಕ್ತಿ 2.5 ಗಂಟೆಗಳ ಕಾಲ 53 kmph ವೇಗದಲ್ಲಿ ವಾಹನ ಚಲಾಯಿಸಿದನು, ನಂತರ ತನ್ನ ವೇಗವನ್ನು 28 kmph ಹೆಚ್ಚಿಸಿದನು ಮತ್ತು ಇನ್ನೊಂದು ಗಂಟೆಯಲ್ಲಿ ತನ್ನ ಗಮ್ಯಸ್ಥಾನವನ್ನು ತಲುಪಿದನು. ಸಂಪೂರ್ಣ ಪ್ರಯಾಣದಲ್ಲಿ ವ್ಯಕ್ತಿಯ ಸರಾಸರಿ ವೇಗವನ್ನು (kmph ನಲ್ಲಿ) ಕಂಡುಹಿಡಿಯಿರಿ.
59
58
60
61
61
Calculate distance: (53 × 2.5) + (81 × 1) = 132.5 + 81 = 213.5. Total time = 3.5. Average = 213.5 / 3.5 = 61.
Speed 1 = 53 kmph for Time 1 = 2.5 hours. Speed 2 = 53 + 28 = 81 kmph for Time 2 = 1 hour.
Average Speed=Total TimeTotal Distance=t1+t2d1+d2
Calculate distance: (53 × 2.5) + (81 × 1) = 132.5 + 81 = 213.5. Total time = 3.5. Average = 213.5 / 3.5 = 61.
Many students mistake 'increased his speed by 28' as the new speed (28 kmph) instead of adding it to the original speed (53 + 28 = 81 kmph).
Calculate distance for the first part
Distance d1=Speed×Time=53×2.5.
d1=132.5 km
Calculate speed and distance for the second part
The speed increased by 28 kmph, so new speed is 53+28=81 kmph for 1 hour.
d2=81×1=81 km
Calculate Total Distance and Total Time
Total distance = 132.5+81=213.5 km. Total time = 2.5+1=3.5 hours.
Dtotal=213.5 km,Ttotal=3.5 hours
Final calculation of Average Speed
Divide total distance by total time: 213.5/3.5.
Avg Speed=3.5213.5=61 kmph
D is correct because the average speed calculated using total distance (213.5 km) divided by total time (3.5 hours) is 61 kmph.
This concept is foundational for 'Relative Speed' and 'Trains' problems, where calculating total distance covered at varied speeds is the primary step.