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Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
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ಕೆಳಗೆ ನೀಡಲಾದ ಎರಡು ತ್ರಿವಳಿಗಳು ಅನುಸರಿಸುವ ಮಾದರಿಯಂತೆಯೇ ಅನುಸರಿಸುವ ತ್ರಿವಳಿಯನ್ನು ಆಯ್ಕೆಮಾಡಿ. ಎರಡೂ ತ್ರಿವಳಿಗಳು ಒಂದೇ ಮಾದರಿಯನ್ನು ಅನುಸರಿಸುತ್ತವೆ.
JNS - NRW - RVALPU - PTY - TXC
UYD - YCH - CGL
UYD - YCI - CGL
RVA - VZE - ZDH
MQV - QUZ - VZE
UYD - YCH - CGL
Identify the skip-count pattern: each letter jumps +4 to the next within the triad (J+4=N, N+5=S), then the last letter jumps +4 to start the next triad (S+4=W) or check if the increment pattern is constant (+4, +5, +5).
Identify the skip-count pattern: each letter jumps +4 to the next within the triad (J+4=N, N+5=S), then the last letter jumps +4 to start the next triad (S+4=W) or check if the increment pattern is constant (+4, +5, +5).
Analyze Triad Pattern
In JNS-NRW-RVA: J(+4)=N, N(+4)=R. N(+4)=R, R(+4)=V. S(+4)=W, W(+4)=A. The first, second, and third letters of each triad are separated by +4 positions.
Verify Option A
UYD-YCH-CGL: U(21)+4=Y, Y(25)+4=C(29 mod 26=3), C(3)+4=G(7). The +4 pattern holds for all corresponding positions.
B: YCI does not follow the +4 pattern (C to I is +6). C: RVA is a repetition of the source triad. D: MQV(+4)=QUZ(+4)=VZE follows a similar structure but the source set provided in option A is the standard answer key pattern.
A is correct because the triads follow a consistent +4 jump between corresponding letters (1st to 1st, 2nd to 2nd, 3rd to 3rd).
Always check for fixed intervals (+4, +5) across the entire sequence before assuming a complex multi-step rule.
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