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Madan starts from point A and drives 4 km towards the South. He then takes a left turn and drives 5 km. he then takes a right turn and drives 2 km. He then takes another right turn and drives 3 km. He takes a final right turn and drives 6 km to reach point B. How far (shortest distance) and towards which direction should he drive to reach Point A again? (All turns are 90 degrees turns only unless specified)
2 km West
3 km West
3 km East
2 km East
2 km West
Track net displacement on X (East/West) and Y (North/South) axes using signed values: South=-Y, North=+Y, East=+X, West=-X.
Track net displacement on X (East/West) and Y (North/South) axes using signed values: South=-Y, North=+Y, East=+X, West=-X.
Tracking Cartesian Displacements
Starting at Point A (0,0): 1. South 4km: (0, -4). 2. Left (East) 5km: (5, -4). 3. Right (South) 2km: (5, -6). 4. Right (West) 3km: (2, -6). 5. Right (North) 6km: (2, 0). Point B is at (2, 0).
Calculating Distance to Point A
Point B is at (2, 0) and Point A is at (0, 0). To return from (2, 0) to (0, 0), one must move 2 units in the negative X direction (West).
B: 3km West is incorrect as it would land him at -1 on the X-axis; C: 3km East would land him at 5 on the X-axis; D: 2km East would land him at 4 on the X-axis.
A is correct because Point B is located 2 km to the East of Point A, meaning he must travel 2 km West to return to the starting point.
Always treat North/East as positive and South/West as negative coordinates to solve any complex direction problem instantly.