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Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
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आर्यन P बिंदूतून निघतो आणि दक्षिणेकडे 4 मी चालतो. त्यानंतर तो डावीकडे वळतो आणि 3 मी चालतो. त्यानंतर तो पुन्हा डावीकडे वळतो आणि 8 मी चालतो. त्यानंतर तो उजवीकडे वळतो आणि 2 मी चालतो. त्यानंतर तो शेवटचे उजवे वळण घेतो आणि Q बिंदूवर थांबण्यापूर्वी 4 मी चालतो. पुन्हा P बिंदूवर पोहोचण्यासाठी त्याने कोणत्या दिशेने चालले पाहिजे? (दिलेल्या माहितीनुसार, सर्व वळणे 90-अंशांची आहेत.)
पूर्व
उत्तर
दक्षिण
पश्चिम
पश्चिम
Map the displacement on a Cartesian plane (X, Y). South is -Y, North is +Y, East is +X, West is -X. Sum the net changes to find the final position relative to the start.
Map the displacement on a Cartesian plane (X, Y). South is -Y, North is +Y, East is +X, West is -X. Sum the net changes to find the final position relative to the start.
Coordinate Mapping
Starting at P(0,0): South 4m → (0,-4). Left(East)₃m → (3,-4). Left(North)₈m → (3,4). Right(East)₂m → (5,4). Right(South)₄m → (5,0).
Path Finalization
Wait, let's re-verify: P(0,0) to South (0,-4). Left turn (facing East) to (3,-4). Left turn (facing North) to (3,4). Right turn (facing East) to (5,4). Right turn (facing South) 4m to (5,0).
Correction Check
If Aryan is at (5,0) and P is (0,0), he must travel 5m West. Reviewing the provided Official Answer D: The logic suggests a net Westward displacement.
A: East would take him further from P, B: North is not the net axis, C: South is not the net axis.
D is correct because based on the coordinate movement, the point Q is located at a net distance to the East of point P, requiring a movement to the West to return to point P.
Always convert direction problems into (X, Y) coordinates to avoid visual confusion during multi-turn sequences.
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